java - 如何从正则表达式中提取值并打印它们并对这些值进行计算

Question

我有一个字符串“规范文件:15 个通过，5 个失败，总共 20 个(100% 完成)，时间为 00:08:53”。

我需要使用正则表达式并打印以下内容:

Passed: 15
Failed: 5
Total: 20

并且还需要计算并打印通过率。请帮忙。

我正在使用以下代码:

String line = "Spec Files:     15 passed, 5 failed, 20 total (100% completed) in 00:08:53";
Pattern p = Pattern.compile("(\\d+)\\s+");
Matcher m = p.matcher(line);
while(m.find()) {
    System.out.println(m.group());
} 

Answer 1

您需要一个正则表达式来捕获您需要的 2 个元素:文本和值，然后按正确的顺序打印它们:

String line = "Spec Files:     15 passed, 5 failed, 20 total (100% completed) in 00:08:53";
Pattern p = Pattern.compile("(\\d+)\\s+(\\w+)");
Matcher m = p.matcher(line);
while (m.find()) {
    System.out.println(m.group(2) + ": " + m.group(1));
}
/*
passed: 15
failed: 5
total: 20

• capitalize 不是内置函数，因此您可以查看 How to capitalize the first character of each word in a string

<小时/>

通过率:

Map<String, Integer> map = new HashMap<>();
while (m.find()) {
    System.out.println(m.group(2) + ": " + m.group(1));
    map.put(m.group(2), Integer.parseInt(m.group(1)));
}
double passPercentage = map.get("passed") / (double) map.get("total");
System.out.println(passPercentage);

或者

    int passed = 0, total = 0;
    while (m.find()) {
        System.out.println(m.group(2) + ": " + m.group(1));
        if (m.group(2).equals("passed")) {
            passed += Integer.parseInt(m.group(1));
        } else if (m.group(2).equals("total")) {
            total += Integer.parseInt(m.group(1));
        }
    }
    double passPercentage = passed / (double) total;
    System.out.println(passPercentage);