java - 需要有关如何将具有相同键的两个值从 json 格式解析为 java map 的建议

Question

我正在努力将 LDAP 中的 ldif 属性读取到我的 java 程序中，我最初的想法是将这些属性放入映射中，然后从中解析它们，但我发现，有一个名为“departmentNumber”的属性，其中包含两个json格式值，

departmentNumber: {"sid":"729999","uid":501,"name":"tebase","role":"managers","title":"sales","groups":["others"]}
departmentNumber: {"sid":"724605","uid":37,"name":"tebase","role":"managers","title":"develope","groups":["leaders"]}

所以我用 map 来放置它们，一些代码如下所示，

但是我的方法只能检索第一个json值，即包含{“sid”:“729999”}的值，但没有包含{“sid”:“724605”}的第二个值，

我观察到程序日志是:

这是从ldif属性读取的日志

2019 22:30:58,237 authentication.mzauth   authentication.mzauth.doAuthenticate(mzauth.java:44)  
{"uid":"brucelee","mail":"brucelee@gm.macom","displayName":"Bruce Lee","givenName":"Bruce Lee","departmentNumber":"{\"sid\":\"729999\",\"uid\":501,\"name\":\"teabas\",\"role\":\"managers\",\"title\":\"sales\",\"groups\":[\"others\"]}","objectClass":"inetOrgPerson","description":"Bruce Lee","sn":"Bruce Lee","cn":"Z39414","department":"000000","info":"2006/02/12"}   

这是放入映射并解析出来的日志

2019 22:30:58,247 services.LdapService services.LdapService.getUser(LdapService.java:251)
ldap user：{"username":"brucelee","fullname":"Bruce Lee","email":"brucelee@gm.macom","departmentid":"729999","titles":[{"schoolid":"729999","titles":["managers","sales"]}],"cloudroles":{"usage":"clouddev","roles":[{"appname":"mail","departmentid":"729999","titles":["managers","sales"]}]},"guid":"c00d5ba660145307c84f2c1e1c557e4ededaf1830029d40aa5b244027","pid":"Z39414","openid":"http://openid.macom/brucelee"}  

正如您所读到的，只有 1 个值，即 sid:72999，而不是两个值，

原来的ldif属性是:

LDAPv3 base with scope subtree filter: uid=brucelee requesting: ALL

Z39414, Managers, developer.alle.com dn: cn=Z39414,ou=Managers,dc=developer,dc=alle,dc=com uid: brucelee userPassword: qwdmsdierf mail: brucelee@gm.macom info: 2006/02/12 sn: Bruce Lee departmentNumber: {"sid":"729999","uid":501,"name":"tebase","role":"managers","title":"sales","groups":["others"]} 　departmentNumber: {"sid":"724605","uid":37,"name":"tebase","role":"managers","title":"develope","groups":["leaders"]} department: 000000 givenName: Bruce Lee objectClass: inetOrgPerson objectClass: organizationalPerson objectClass: person objectClass: top cn: Z39414 displayName: Bruce Lee description: Bruce Lee

搜索结果 搜索:2 结果: 0 成功 回复数量:2 条目数:1

我的问题是，如何将两个json值都放入我的map中，或者我对map的使用是错误的，有更好的方法来处理这种情况吗？

public DataModel getUser(String uid, String passwd, String role, DataModel   user) throws Exception {
private Map<String, String> map = null;
   if (role.equals("managers")) {
            map = Ldap.getAttrubites(ldapurl, uid, passwd);
            List<Titles> titlesArray = new ArrayList<>();
            List<Roles> rolesArray = new ArrayList();
            map.forEach((key, value)
                    -> {logger.info("{} - {}", key, value); });
     if (key.equals("departmentNumber")) {
                List<StringModel> model = map.get("departmentNumber")).get();
                model.stream().forEach(k -> {
                for (int i = 0; i < model.size(); i++) {
                            Titles titles = new Titles();
                            List<String> titleList = new ArrayList<>();
                            String userid = model.get(i).getUid();
                            String mtitle = model.get(i).getRole();
                            String subtitle = model.get(i).getTitle();
                            titleList.add(mtitle);
                            titleList.add(subtitle);
                            titles.setSchoolid(schoolid);
                            titles.setTitles(titleList);
                            titlesArray.add(titles);

                 ........ });}
                 user.setTitles(titlesArray);
                 .........;
    } return user;
    }

Answer 1

java.util.Map<K,V>接口(interface)只为每个键保存一个值。如果要为每个键保存多个值，则需要为V指定一个集合类。部分。例如，如下所示。

Map<String, List<String>> map = ...

<a href="https://docs.oracle.com/javaee/7/api/javax/ws/rs/core/MultivaluedMap.html" rel="noreferrer noopener nofollow">javax.ws.rs.core.MultivaluedMap</a> Java EE API 中定义的接口(interface)是实现您想要做的事情的示例。