java - varArgs 计算数字总和的示例(独立于输入参数的数量调用相同的方法)

Question

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已关闭 10 年前。

Possible Duplicate:
java: how can i create a function that supports any number of parameters?

有没有办法从其他函数调用通用函数，而不管输入参数如何？如果我的输入数据类型全部相同(仅 int 或仅 String)

public class sumOfNo {

public static void main(String[] arg) {

    /**
     * Normal way of calling function to calculate sum.
     */
     int result = sum(1, 2);
     int result1 = sum(1, 2, 3);

}

/**
 * A normal function overloading method of calculating sum
 * @return
 */

 private static int sum(int i, int i0) {
     int c = i + i0;
     System.out.println("c:" + c);
     return c;
 }

 private static int sum(int i, int i0, int i1) {
     int c = i + i0 + i1;
     System.out.println("c:" + c);
     return c;
 }

}

Answer 1

尝试这样的事情

public int sum(int... args) {  
  int sum = 0;  
  for (int i : args)  
    sum += i;  
  return sum;  
}

然后你就可以调用

sum(3);
sum(3, 4, 5);
sum(3, 4, 5, 6, 7);

erit:amit 快了 5 秒:)