php - Laravel Faker 工厂关系

Question

我有两个工厂，一个负责品类，另一个负责产品。当我经营工厂时，我想为每个生成的类别创建 x 数量的产品。我将如何编写代码来生成此产品？

类别的定义是这样写的:

return [
            'name' => $this->faker->word,
            'slug' => Str::slug($this->faker->unique()->word, '-'),
        ];

产品的定义是这样写的:

return [
                'category_id' => 1, //instead of 1 the category id used i want to be random
                'name' => $this->faker->word,
                'slug' => Str::slug($this->faker->unique()->word, '-'),
                'description' => $this->faker->paragraph,
                'price' => $this->faker->randomFloat(2, 0, 10000),
                'is_visible' => 1,
                'is_featured' => 1
            ];

如您所见，我对 category_id 进行了硬编码，我不太确定如何让它自动生成并为每个存在的类别创建产品。我有这样写的类别的工厂，以创建 10 个项目

Category::factory()
                ->count(10)
                ->create();

我尝试过尝试和错误，认为它会起作用，但我得到一个错误，即 category_id cannot be null 。

Product::factory()
                ->has(Category::factory()->count(2))
                ->count(20)
                ->create();

Answer 1

    $factory->define(Product::class, function (Faker $faker) {
    return [
        'category_id' => factory(Category::class), //instead of 1 the category id used i want to be random
        'name' => $this->faker->word,
        'slug' => Str::slug($this->faker->unique()->word, '-'),
        'description' => $this->faker->paragraph,
        'price' => $this->faker->randomFloat(2, 0, 10000),
        'is_visible' => 1,
        'is_featured' => 1
    ];
});

通过将属性设置为 factory() 的实例，Laravel 也会懒惰地创建该模型并自动关联它