java - 第一、第二大金额

Question

问题是:

Write a program that prompt the user to enter 5 numbers and find the two largest values among them. If the user enters number more than 100 or less than – 100 the program should exit.

Hint: use break.

我的代码是:

import java.util.*;

public class q2 {
    static Scanner scan = new Scanner (System.in);
    public static void main (String[] args ) {

        int num;
        int max=0;//define Maximum value and save it in variable max = 0;
        int secondMax=0;//define the second maximum value and save it in variable secondMax = 0;

        System.out.println("Please , Enter 5 numbers between 100 and -100 "); //promet user to enter 5 numbers with the condition

        for (int count=0 ; count<5 ; count++) // start loop with (for) 
        {
            num = scan.nextInt();//user will enter number it will be repeated 5 times .

            if( num > 100 || num<-100) //iv the user enter a number less than -100 or geater than 100 program will quit from loop
            {
                System.out.println("The number you have entered is less than -100 or greater than 100 ");//telling the user what he did
                break;//End the loop if the condition ( num > 100 || num<-100) is true .
            }
            if(num>max )//Another condition to find the maximum number
                max = num;//if so , num will be saved in (max)

            if (num >= secondMax && num < max)// A condition to find the second Maximum number
                secondMax = num;//And it will be saved in (secondMax)
        }//End loop
        System.out.println("The largest value is " + max); //Print the largest number
        System.out.println("The second largest value is " + secondMax );//print the second largest number .
    }//End main

}//End class

这是我的代码输出:

Please , Enter 5 numbers between 100 and -100 
20
30
60
20
-10
The largest value is 60
The second largest value is 20

第二大数字不正确 - 20，而不是 30。我做错了什么？

Answer 1

可以有两种情况，

1. 您找到新的最大值，在本例中，更新 secondarymax 并将该数字设置为 max
2. 您找到新的 SecondMax，仅更新 SecondMax

试试这个

if(num>secondMax&&num<max)   // case 2
{
    secondMax = num
} 
else if(num>max)   // case 1
{
    secondMax = max;
    max = num;
}