java - 将两个字符串从一个 Activity 传递到另一个 Activity

Question

我正在开发一个适用于 Android 的 tic tac toe 应用程序。在“两名玩家”部分中，我创建了一个 Activity ，要求两名玩家输入他们的名字。为此，我使用了两个 EditTexts。问题是我的应用程序在开始下一个 Activity 时关闭。这是我的代码:

//Activity 1:
    EditText player1field,player2field;
    Button startbutton;
    Intent startbuttonintent;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.single_options);
    setupActionBar();
    player1field = (EditText) findViewById(R.id.player1field);
    player2field = (EditText) findViewById(R.id.player2field);
    startbuttonintent = new Intent(this, Activity2.class);
    startbutton.setOnClickListener(new View.OnClickListener()
    {
        @Override
        public void onClick(View v) {

            String player1name = player1field.getText().toString();
            String player2name = player2field.getText().toString();
            startbuttonintent.putExtra("PLAYER1NAME",player1name);
            startbuttonintent.putExtra("PLAYER2NAME",player2name);
            startActivity(startbuttonintent);
        }
    });
}

这是 Activity 2

//Activity2
Intent startbuttonintent = getIntent();
TextView p1name,p2name;
    public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_3m);

    String player1name = startbuttonintent.getStringExtra("PLAYER1NAME");
    String player2name = startbuttonintent.getStringExtra("PLAYER2NAME");
    p1name = (TextView) findViewById(R.id.p1name);
    p2name = (TextView) findViewById(R.id.p2name);
    p1name.setText(player1name);
    p2name.setText(player2name);
}

这段代码没有给我任何错误，但当我运行它时，我的应用程序强制关闭。请帮我。提前致谢。

Answer 1

试试这个:

Activity 1:

    EditText player1field,player2field;
    Button startbutton;
    Intent startbuttonintent;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.single_options);
    setupActionBar();
    player1field = (EditText) findViewById(R.id.player1field);
    player2field = (EditText) findViewById(R.id.player2field);        
    startbutton.setOnClickListener(new View.OnClickListener()
    {
        @Override
        public void onClick(View v) {

            String player1name = player1field.getText().toString();
            String player2name = player2field.getText().toString();
            startbuttonintent = new Intent(this, Activity2.class);
            startbuttonintent.putExtra("PLAYER1NAME",player1name);
            startbuttonintent.putExtra("PLAYER2NAME",player2name);
            startActivity(startbuttonintent);
        }
    });
}

您在onclick之前调用了此方法，这会导致错误。

并像这样获取 Intent 文本:

//Activity 2

TextView p1name,p2name;
  public void onCreate(Bundle savedInstanceState)
{
  super.onCreate(savedInstanceState);
  setContentView(R.layout.activity_3m);
  Bundle extras = getIntent().getExtras();
  String player1name = extras.getString("PLAYER1NAME");
  String player2name = extras.getString("PLAYER2NAME");
  p1name = (TextView) findViewById(R.id.p1name);
  p2name = (TextView) findViewById(R.id.p2name);
  p1name.setText(player1name);
  p2name.setText(player2name);
}