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java - 如何将另一个类对象添加到列表中

转载 作者:行者123 更新时间:2023-12-01 23:23:51 25 4
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我有一个玩家类和 friend 类,玩家类中有 friend 对象。但 friend 类别也具有与玩家类别相同的字段。如何将好友列表添加到玩家。就像在 Facebook 上一样,用户的 friend 列表中有 friend 。如何使 PlayerController 类中的注释方法起作用?

//@CrossOrigin(origins = "http://localhost:4200")
@RestController
@RequestMapping(value = "/players", produces = { MediaType.APPLICATION_JSON_VALUE })
public class PlayerController {

@Autowired
private PlayerReopsitory playerReopsitory;

@GetMapping(produces = "application/json")
public List<Player> getAllPlayers(){
return playerReopsitory.findAll();
}

@PostMapping
// @ResponseStatus(HttpStatus.OK)
public void create(@RequestBody Player player) {
playerReopsitory.save(player);
}

@GetMapping("/{id}")
public Player getOne(@PathVariable("id") Long id) {
return playerReopsitory.getOne(id);
}

@DeleteMapping("/{id}")
void deletePlayer(@PathVariable Long id) {
playerReopsitory.deleteById(id);
}

@PutMapping("/{id}")
Player updatePlayer(@RequestBody Player newPlayer, @PathVariable Long id) {

return playerReopsitory.findById(id).map(player -> {
player.setName(newPlayer.getName());
player.setEmail(newPlayer.getEmail());
player.setPhone(newPlayer.getPhone());
return playerReopsitory.save(player);
}).orElseGet(() -> {
newPlayer.setId(id);
return playerReopsitory.save(newPlayer);
});
}


// how to make this function work?
// @GetMapping("/{id}/friends")
// public List<Friend> getAllFriendFromList(@PathVariable Long id) {
// return playerReopsitory.findById(id).get();
// }
//

}
@Entity
@Table(name= "user", schema = "rabbit")
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
public class Friend {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

@Column(name="userName")
private String userName;

@Column(name="playername")
private String name;

@Column(name="email")
private String email;

@Column(name="phone")
private String phone;

public Long getId() {
return id;
}

public void setId(Long id) {
this.id = id;
}

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public String getPhone() {
return phone;
}

public void setPhone(String phone) {
this.phone = phone;
}

@Override
public String toString() {
return "Friend [id=" + id + ", userName=" + userName + ", name=" + name + ", email=" + email + ", phone="
+ phone + "]";
}
}

@Entity
@Table(name= "user", schema = "rabbit")
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
public class Player {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

@Column(name="userName")
private String userName;

@Column(name="playername")
private String name;

@Column(name="email")
private String email;

@Column(name="phone")
private String phone;

private Friend friend;




public Friend getFriend() {
return friend;
}

public void setFriend(Friend friend) {
this.friend = friend;
}

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public String getPhone() {
return phone;
}

public void setPhone(String phone) {
this.phone = phone;
}


public Long getId() {
return id;
}

public void setId(Long id) {
this.id = id;
}



@Override
public String toString() {
return "Player [id=" + id + ", userName=" + userName + ", name=" + name + ", email=" + email + ", phone="
+ phone + ", friend=" + friend + "]";
}

public interface FriendReopsitory extends JpaRepository<Player, Long> {

}

public interface PlayerReopsitory extends JpaRepository<Player, Long> {

}
@Component
public class FriendService {


private static Map<Friend, Long> getFriends = new HashMap<>();{

}
}

最佳答案

由于 friend 也是玩家,我建议您重构您的模型,使其只有一个玩家类,与其自身具有多对多的关系。

@Entity
public class Player {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

/*
* Add other fields
*/

@ManyToMany()
@JoinTable(name = "player_friends", joinColumns = {
@JoinColumn(name = "PLAYER_ID", referencedColumnName = "ID")
}, inverseJoinColumns = {
@JoinColumn(name = "FRIEND_ID", referencedColumnName = "ID")
})
private List<Player> friends;

/*
* Add other getters and setters
*/

public List<Player> getFriends() {
return this.friends;
}

/*
* Implement addFriend and removeFriend methods
*/
}

然后,您将需要处理集合加载(LAZY 或 EAGER)、添加和删除友元方法。但这不属于本问题的范围,您可以在网上找到有关此主题的大量资源。

关于java - 如何将另一个类对象添加到列表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58315170/

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