java - 从 yml 配置获取值到依赖项

Question

我上课了:

@WebServiceClient(name = "${service.name}", targetNamespace = "${service.namespace}", wsdlLocation = "${service.wsdlLocation}")
public class ExampleService extends Service {
    @Value("${service.wsdlLocation}")
    private static String wsdlLocation;
}

它是 mvn 项目的一部分，我从本地 Maven 存储库编译并使用它作为我的其他 spring-boot 应用程序的依赖项，该应用程序具有配置 yml:

service:
  name: name
  namespace: namespace
  wsdlLocation: wsdlLocation

有没有办法让这个ExampleService类使用“父”项目的配置？

编辑:

出现了两个答案，但我觉得我没有问清楚。我现在想做的是在我的“父”项目中使用类 ExampleService 并使其看到该父项目的配置。到目前为止，例如我在父项目代码中编写如下内容:

ExampleService exampleService = new ExampleService();
System.out.println(exampleService.getWsdlLocation());

打印 Null。所以我正在寻找一些解决方案。

编辑2:这是我的类(class)。父项目:

package com.example.kris.parentservice;

import com.example.kris.childservice.ExampleService;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;

@RestController
@RequestMapping("/example")
public class ExampleController {

//    @Autowired
    private ExampleService exampleService;
    @Value(value = "${service.wsdlLocation}")
    private String wsdlLocation;

    @GetMapping(value = "/example")
    public void example() {
        exampleService = new ExampleService();
        System.out.println("ExampleService field: " + exampleService.getWsdlLocation());
        System.out.println("@Value: " + wsdlLocation);
    }
}

子项目:

package com.example.kris.childservice;

import org.springframework.beans.factory.annotation.Value;

public class ExampleService {
    @Value("${service.wsdlLocation}")
    private String wsdlLocation;

    public String getWsdlLocation() {
        return wsdlLocation;
    }
}

运行父 Controller 后输出:

ExampleService field: null
@Value:test.wsdl.location

Answer 1

YamlPropertySourceLoader 在 Spring Boot 应用程序注入(inject)像这样的 bean 时很有帮助

@Bean
public PropertySource<?> yamlPropertySourceLoader() throws IOException {
    YamlPropertySourceLoader loader = new YamlPropertySourceLoader();
    PropertySource<?> applicationYamlPropertySource = loader.load("application.yml",
            new ClassPathResource("application.yml"), "default");
    return applicationYamlPropertySource;
}