java - 用Java猜数字程序

Question

我正在尝试用 Java 创建一个程序，其中计算机随机猜测 1-100 之间的数字，并允许用户猜测该数字。

如果该数字低于随机数，程序应显示:lower!，如果高于随机数，程序应显示:higher!

如果用户猜对了正确的数字，它应该说恭喜您在 X 次尝试中猜对了正确的数字。

这就是我到目前为止所拥有的，任何帮助将不胜感激!

import java.util.Scanner;

public class QuestionOne
{
  public static void main(String args[])
  {
   Scanner keyboard = new Scanner(System.in);

   int a = 1 + (int) (Math.random() * 99);
   int guess;

   System.out.println("I am thinking of a number from 1 to 100 ... guess what it is ?");
   guess = keyboard.nextInt();

   while(guess != a){
   if (guess > a)
   {  
     System.out.println("lower!");

   }
   else if (guess < a) 
   {
    System.out.println("higher!");

   }
   else 
   {
     System.out.println("Congratulations.   You guessed the number with X tries!");
   }
   }
  }
}

Answer 1

您忘记在每个循环中从扫描仪获取一个新的 int :)

import java.util.Scanner;

public class QuestionOne
{
  public static void main(String args[])
  {
   Scanner keyboard = new Scanner(System.in);

   int a = 1 + (int) (Math.random() * 99),
       guess, 
       count = 0;

   System.out.println("I am thinking of a number from 1 to 100 ... guess what it is ?");

   while((guess = keyboard.nextInt()) != a){
     if (guess > a)
     {  
       System.out.println("lower!");
     }
     else
     {
       System.out.println("higher!");
     }
     count++;
   }

   System.out.println("Congratulations.   You guessed the number with "+ count +" tries!");
  }

}

编辑:我现在很无聊...添加计数器;)