java - 如果第一个为真，则不要运行第二个

Question

你好，我是 Java 新手，在阅读了一些相关内容后，我尝试编写一个小程序。该程序包含两个 if 堆栈，我希望如果第一个堆栈解决程序结束并且根本不读取第二个堆栈。这是我想出的代码:

扫描仪 myScanner = new Scanner(System.in);

     String independent1 = "money";
     String independent2 = "succes";
     String independent3 = "career";
     String userInput; 
     int randomNumber;
     System.out.println("I'm listening mortal. Pick your topic.");

     userInput = myScanner.next();



          if(independent1.equals(userInput))
            System.out.println("You should rely on yourself more than                  on mystic forces like me");
          if(independent2.equals(userInput))
                System.out.println("You should rely on yourself more than on mystic forces like me");
          if(independent3.equals(userInput))
                System.out.println("You should rely on yourself more than on mystic forces like me");

          Random myRandom = new Random();
            randomNumber =myRandom.nextInt(100)+1;    
                  if (randomNumber >= 50){
          System.out.println(randomNumber);
           System.out.println("Yes");
         } else {
          System.out.println(randomNumber);
          System.out.println("No!");

我想如果“独立如果”为真，则程序结束并且不运行第二个程序，有人可以帮助我吗？

Answer 1

使用if/else if

if(independent1.equals(userInput)){
....
} else if(independent2.equals(userInput)){
....
} else if(independent3.equals(userInput)){
...
}

如果您使用java 1.7您还可以将 switch 语句与字符串一起使用。它们的介绍是 JSR 334 .

switch(userInput){
    case "money":
        ....
        break;
    case "succes":
        ....
        break;
    case "career":
        ....
        break;
}