merge - 数据表 - 将列合并在一起

Question

我有这些数据库列，但我希望它们位于一列中。我该怎么做呢？我想是用 mRender 吧？

                    /* Address */  
        {"sTitle": "Address",
                    "bVisible": true,
                    "bSearchable": true},
        /* City */   
        {"sTitle": "City",
                    "bVisible": true,
                    "bSearchable": true},
        /* State */    
        {"sTitle": "State",
                    "bVisible": true,
                    "bSearchable": true},
        /* Zip */    
        {"sTitle": "Zip",
                    "bVisible": true,
                    "bSearchable": true},

Answer 1

假设数据表 get 返回的列是地址、城市、州、邮政编码 1-4

如果返回的数据是常规数组

   { "mData": 0 , //or address field
     "mRender" : function ( data, type, full ) { 
     //data = mData
     //full is the full array address= [0] city = [1] state=[2] zip=[3] 
        return data+', '+full[1]+', '+full[2]+', '+full[3];}
      },

如果您的数据是关联数组

   { "mData": 'address' , 
     "mRender" : function ( data, type, full ) { 
        return data+', '+full['city']+', '+full['state']+', '+full['zip'];}
      },

或者你可以独立于mData调用mRender(尽管这种情况似乎不需要)

   { "mData": null , 
     "mRender" : function ( data, type, full ) { 
        return full['address']+', '+full['city']+', '+full['state']+', '+full['zip'];}
      },

编辑:对于数据表 1.10，只需稍微更改名称，删除“m”

   { "data": null , 
     "render" : function ( data, type, full ) { 
        return full['address']+', '+full['city']+', '+full['state']+', '+full['zip'];}
      },

*注意，我没有考虑您是否应该将此数据存储在一列中，只是显示其完成方式