java - 无法捕获算术异常(不过捕获 IllegalArgumentException 没问题)

Question

请看下面我的构造函数，我正在从字符串创建一个分数:

public Fraction(String str)
    {
        if(str.isEmpty())
        {
            throw new IllegalArgumentException("The str (String) parameter cannot be empty!");
        }
             int[] fractionData= new int[2];
             String[] data = str.split("/");
             try
             {
                 if(data.length==0)
                 throw new IllegalArgumentException("The str (String) parameter cannot be empty");
             }
             catch (IllegalArgumentException ex)
             {
                 System.out.println(ex.toString());
             }
             try
             {
                fractionData[0] = Integer.parseInt(data[0]); 
             }
             catch (IllegalArgumentException ex)
             {
                 System.out.println(ex.toString());
             }

             try
             {
                 fractionData[1] = Integer.parseInt(data[1]);
                 if(fractionData[1]==0) throw new ArithmeticException("Denominator can't be 0");
             }
             catch (ArithmeticException ex)
             {
                 System.out.println(ex.toString());
             }
             fractionData = normalize(fractionData[0],fractionData[1]);
             this.numerator = fractionData[0];
             this.denominator = fractionData[1];
    }

我很好地捕获了 IllegalArgumentException，但未能捕获 ArithmticException。我可以成功测试两者

@Test(expected=IllegalArgumentException.class)
    public void testIllegalArgumenException() throws IllegalArgumentException
    {
        Fraction g =  new Fraction("");
    }
    @Test(expected=ArithmeticException.class)
    public void testArithmeticException() throws ArithmeticException
    {
        Fraction g = new Fraction(1/0);
    }

感谢@xp500的评论，我已将代码更改为:

public Fraction(String str)
    {
        if(str.isEmpty()) throw new IllegalArgumentException("The str (String) parameter cannot be empty!");
             int[] fractionData= new int[2];
             String[] data = str.split("/");
             if (data.toString().matches("[a-zA-Z]+")) throw new NumberFormatException("only numbers allowed in the string");
             fractionData[0] = Integer.parseInt(data[0]);
             fractionData[1] = Integer.parseInt(data[1]);
             if(fractionData[1]==0) throw new ArithmeticException("Denominator can't be 0"); 
             fractionData = normalize(fractionData[0],fractionData[1]);
             this.numerator = fractionData[0];
             this.denominator = fractionData[1];
    }

它不会引用“仅字符串中允许的数字”，但会停止将分数初始化为 0/0，以防使用带有字母的字符串来初始化分数，并抛出带引号文本的其他异常。我学到的教训是:不要捕捉异常，除非你实际上正在对它们做一些事情

Answer 1

你正在捕获ArithmeticException，但你没有追溯它(像其他异常一样)