gpt4 book ai didi

sql - 从数字序列动态创建范围

转载 作者:行者123 更新时间:2023-12-01 23:10:42 25 4
gpt4 key购买 nike

我有一张如下表:

+----+-----+-----+
| ID | GRP | NR |
+----+-----+-----+
| 1 | 1 | 101 |
| 2 | 1 | 102 |
| 3 | 1 | 103 |
| 4 | 1 | 105 |
| 5 | 1-2 | 106 |
| 6 | 1-2 | 109 |
| 7 | 1-2 | 110 |
| 8 | 2 | 201 |
| 9 | 2 | 202 |
| 10 | 3 | 300 |
| 11 | 3 | 350 |
| 12 | 3 | 351 |
| 13 | 3 | 352 |
+----+-----+-----+

我想创建一个 View ,该 View 按 GRP 对该列表进行分组,并将 NR 中的值连接起来。是否可以动态检测序列并将其缩短为范围?就像 1, 2, 3, 5 会变成 1-3, 5

所以结果应该是这样的:

+-----+--------------------+
| GRP | NRS |
+-----+--------------------+
| 1 | 101 - 103, 105 |
| 1-2 | 106, 109 - 110 |
| 2 | 201 - 202 |
| 3 | 300, 350 - 352 |
+-----+--------------------+

我现在得到的只是连接值,所以上面的表格会变成这样:

+-----+--------------------+
| GRP | NRS |
+-----+--------------------+
| 1 | 101, 102, 103, 105 |
| 1-2 | 106, 109, 110 |
| 2 | 201, 202 |
| 3 | 300, 350, 351, 352 |
+-----+--------------------+

这是实际的声明:

DECLARE @T TABLE
(
ID INT IDENTITY(1, 1)
, GRP VARCHAR(10)
, NR INT
)
INSERT INTO @T
VALUES ('1',101),('1',102),('1',103),('1',105)
,('1-2',106),('1-2',109), ('1-2',110)
,('2',201),('2',202)
,('3',300),('3',350),('3',351),('3',352)

SELECT * FROM @T

;WITH GROUPNUMS (RN, GRP, NR, NRS) AS
(
SELECT 1, GRP, MIN(NR), CAST(MIN(NR) AS VARCHAR(MAX))
FROM @T
GROUP BY GRP

UNION ALL

SELECT CT.RN + 1, T.GRP, T.NR, CT.NRS + ', ' + CAST(T.NR AS VARCHAR(MAX))
FROM @T T
INNER JOIN GROUPNUMS CT ON CT.GRP = T.GRP
WHERE T.NR > CT.NR
)
SELECT NRS.GRP, NRS.NRS
FROM GROUPNUMS NRS
INNER JOIN (
SELECT GRP, MAX(RN) AS MRN
FROM GROUPNUMS
GROUP BY GRP
) R
ON NRS.RN = R.MRN AND NRS.GRP = R.GRP
ORDER BY NRS.GRP

谁能告诉我这样做是否容易?如果有人有想法并愿意分享,那就太好了。

最佳答案

SQLFiddle demo

with TRes 
as
(
select T.GRP,T.NR NR,
CASE WHEN T1.NR IS NULL and T2.NR is null
THEN CAST(T.NR as VARCHAR(MAX))
WHEN T1.NR IS NULL and T2.NR IS NOT NULL
THEN '-'+CAST(T.NR as VARCHAR(MAX))
WHEN T1.NR IS NOT NULL and T2.NR IS NULL
THEN CAST(T.NR as VARCHAR(MAX))+'-'
END AS NR_GRP


from T
left join T T1 on T.Grp=T1.Grp and t.Nr+1=t1.Nr
left join T T2 on T.Grp=T2.Grp and t.Nr-1=t2.Nr

WHERE T1.NR IS NULL or T2.NR IS NULL

)
SELECT
GRP,
REPLACE(
substring((SELECT ( ',' + NR_GRP)
FROM TRes t2
WHERE t1.GRP = t2.GRP
ORDER BY
GRP,
NR
FOR XML PATH( '' )
), 2, 10000 )
,'-,-','-')
FROM TRes t1
GROUP BY GRP

关于sql - 从数字序列动态创建范围,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16517570/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com