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Java : Sort a List with neighbour

转载 作者:行者123 更新时间:2023-12-01 23:03:39 25 4
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我有一个 Point 列表,我想将它们与它们的邻居一起排序。

例如:
列表初始化

(0,0); (1,0); (5,0); (6,0);  
(0,1); (1,1); (5,1); (6,1);

列表排序

(0,0); (1,0); (0,1); (1,1);  
(5,0); (6,0); (5,1); (6,1);

我怎样才能做到这一点?

list.sort(new Comparator<Point>() {
@Override
public int compare(Point p1, Point p2) {
// Euclidian distance or something like that
return ;
}
});

最佳答案

实现比较器以获得您想要的排序。示例:

Collections.sort(list, new Comparator<Point>()
{
public int compare(Point p1, Point p2)
{
//Euclidean distance from 0,0
Point origin = new Point();
return Double.compare(p1.distance(origin), p2.distance(origin));
}
});

或者,使用 java 8 lambda 表达式:

Collections.sort(list, ((p1, p2) -> Double.compare(p1.distance(0, 0), p2.distance(0, 0));

关于Java : Sort a List<Point> with neighbour,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23143735/

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