c# - 打包(.zip)一个字节数组文件.net core

Question

我试着按照这个 SO: Create zip file from byte[]作为一个虚拟项目，它看起来像这样:

using System.IO.Compression;
using System.IO;
using System.Net.Http;
using System;

namespace TestApp
{
    internal class Program
    {
        static void Main(string[] args)
        {
            using var compressedFileStream = new MemoryStream();
            using var zipArchive = new ZipArchive(compressedFileStream, ZipArchiveMode.Create);

            //Create a zip entry for each attachment
            var zipEntry = zipArchive.CreateEntry("test.txt");
            var file = File.ReadAllBytes("test.txt");

            //Get the stream of the attachment
            using var originalFileStream = new MemoryStream(file);
            using var zipEntryStream = zipEntry.Open();
            //Copy the attachment stream to the zip entry stream
            originalFileStream.CopyTo(zipEntryStream);

            var toarraybaby = compressedFileStream.ToArray();

            File.WriteAllBytes("hehe.zip", toarraybaby);
        }
    }
}

我得到一个 .zip 文件作为输出，该文件有一个大小。但是当试图打开文件时，我发现它已损坏。我错过了什么？

Answer 1

该代码的具体问题在于 C# 8 风格的 using 声明将 at 置于当前作用域的末尾。那太晚了。必须处理 zip 存档以确保将所有必要的数据写入其输出流，但在执行此操作时，Main 已结束。

有多种方法可以确保它尽早处理，例如:

using var compressedFileStream = new MemoryStream();
// using an old-style using statement here to ensure the zip archive gets disposed early enough
using (var zipArchive = new ZipArchive(compressedFileStream, ZipArchiveMode.Create))
{
    //Create a zip entry for each attachment
    var zipEntry = zipArchive.CreateEntry("test.txt");
    var file = File.ReadAllBytes("test.txt");

    //Get the stream of the attachment
    using var originalFileStream = new MemoryStream(file);
    using var zipEntryStream = zipEntry.Open();
    //Copy the attachment stream to the zip entry stream
    originalFileStream.CopyTo(zipEntryStream);

}
var toarraybaby = compressedFileStream.ToArray();

File.WriteAllBytes("hehe.zip", toarraybaby);