java - 如何重新运行任务

Question

我有一个任务正在运行，如果失败，我想再次运行它最多三次。问题是 Android 会因为我试图在它自己内部运行任务而生气。解决这个问题的最佳方法是什么？

代码(查看底部的task.callback):

final GenericAsyncTask task = new GenericAsyncTask();

        task.background = new Runnable() {
            public void run() {
                HttpClient httpclient = new DefaultHttpClient();
                HttpPost httppost = new HttpPost(GCMIntentService.this.host);
                String addremove = "add";
                if(register == false) addremove = "remove";

                try {
                    // Add your data
                    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);
                    nameValuePairs.add(new BasicNameValuePair("cmd", addremove));
                    nameValuePairs.add(new BasicNameValuePair("subscription_key", SUBSCRIPTION_KEY)); // unique per app
                    nameValuePairs.add(new BasicNameValuePair("token", str));
                    nameValuePairs.add(new BasicNameValuePair("os_family", "android"));
                    if(addremove.equals("remove")) nameValuePairs.add(new BasicNameValuePair("hard", "" + hard));
                    UrlEncodedFormEntity entity = new UrlEncodedFormEntity(nameValuePairs);
                    httppost.setEntity(entity);
                    Log.i(LCHApplication.TAG, "Name Value Pairs: " + nameValuePairs.toString());

                    // Execute HTTP Post Request
                    HttpResponse response = httpclient.execute(httppost);
                    task.result = EntityUtils.toString(response.getEntity());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        };

        task.callback = new Runnable() {
            public void run() {
                try {
                    Log.i(LCHApplication.TAG, "registration response: " + task.result.toString());
                } catch(Exception e) {
                    if(attempts++ < ATTEMPTS_LIMIT) {
                        // try to register the device again
                        task.execute();
                    } else {
                        Crashlytics.logException(e);
                    }
                }
            }
        };

        task.execute();

Answer 1

The issue is that Android gets mad that I'm trying to run a task inside of it's self

除此之外，AsyncTask 是一次性对象。您无法重新execute() AsyncTask 实例。

What's the best way to get around this?

创建 AsyncTask 的新实例。例如，您可以实现一个复制构造函数，用于从先前执行的实例克隆一个新实例。

或者，不要使用AsyncTask。

我不能说这些与任何 GenericAsyncTask 的配合效果如何，因为 Android SDK 中没有 GenericAsyncTask。