java - java中json多个json数据解析

Question

我有一个像这样的 json 输入

[ {
    "Company":"BEG",
    "Account":"1001",
    "Deptid":"",
    "Location":"",
    "Transaction Date":"2014-07-15",
    "Description":"Invoice",
    "Debit":0.0,
    "Credit":13.46,
    "Invoice Nbr":"1682"
    },
    {
    "Company":"BEG2",
    "Account":"1002",
    "Deptid":"23",
    "Location":"NY",
    "Transaction Date":"2014-07-15",
    "Description":"Invoice",
    "Debit":0.0,
    "Credit":13.45,
    "Invoice Nbr":"1682432"
    },
    ....
    ....
    },
    {
    "Company":"BEG99",
    "Account":"1099",
    "Deptid":"",
    "Location":"",
    "Transaction Date":"2014-07-15",
    "Description":"Invoice",
    "Debit":0.0,
    "Credit":13.46,
    "Invoice Nbr":"168243299"
    }]

我正在使用 json simple jar 来解析 json。我的代码是:

public String appendData(String str) throws IOException, ParseException{
        System.out.println("========Inside appendData======"+str);
        JSONParser jsonParser = new JSONParser();
        JSONObject jsonObject = (JSONObject) jsonParser.parse(new StringReader(str));
        double debit = (double) Double.parseDouble(jsonObject.get("Debit").toString());
}

如果我发送单个数据锁并且没有 [ 和 ] 括号，上面的代码工作正常。上面的json是根据JSONLint的有效json

问题:

1) 如何解析上面包含多个数据的 json？

Answer 1

如果您想使用 json-simple，则适合您的场景，如下所示:

JSONParser jsonParser = new JSONParser();
                Object obj =  jsonParser.parse(new StringReader(str));
            if (obj instanceof JSONObject) {
                JSONObject jo = (JSONObject) obj;
                 System.out.println(jo.get("Debit").toString());
            } else {
                JSONArray ja = (JSONArray) obj;
                for(int i=0;i<ja.size();i++){
                    JSONObject   jsonObject = (JSONObject)ja.get(i);
                    System.out.println(jsonObject.get("Debit").toString());
                }
            }