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odoo - 创建序列号odoo 10

转载 作者:行者123 更新时间:2023-12-01 22:40:58 25 4
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我想创建一个序列号 odoo 10(有些人认为像 OM-201709-001)我将此代码用于:

*.xml

<openerp>
<data noupdate="1">
<record id="seq_type_id" model="ir.sequence.type">
<field name="name">omega_sequence</field>
<field name="code">hr.employee</field>
</record>

<record id="seq_id" model="ir.sequence">
<field name="name">omega_sequence</field>
<field name="code">hr.employee</field>
<field name="prefix">SQ</field>
<field name="padding">5</field>
<!--<field name="suffix">suffix</field>-->
</record>

</data>
</openerp>

对于:

*.py

class omega(models.Model):
_name = 'omega.model'
_description = 'No Description for now !!'

sequence_id = fields.Char('Sequence', readonly=True)

@api.model
def create(self, vals):
seq = self.env['ir.sequence'].get('hr.employee') or '/'
vals['sequence_id'] = seq
return super(omega, self).create(vals)

但是无论我做什么,我总是会遇到这个错误:

Traceback (most recent call last):
File "/opt/odoo/odoo/http.py", line 640, in _handle_exception
return super(JsonRequest, self)._handle_exception(exception)
File "/opt/odoo/odoo/http.py", line 677, in dispatch
result = self._call_function(**self.params)
File "/opt/odoo/odoo/http.py", line 333, in _call_function
return checked_call(self.db, *args, **kwargs)
File "/opt/odoo/odoo/service/model.py", line 101, in wrapper
return f(dbname, *args, **kwargs)
File "/opt/odoo/odoo/http.py", line 326, in checked_call
result = self.endpoint(*a, **kw)
File "/opt/odoo/odoo/http.py", line 935, in __call__
return self.method(*args, **kw)
File "/opt/odoo/odoo/http.py", line 506, in response_wrap
response = f(*args, **kw)
File "/opt/odoo/addons/web/controllers/main.py", line 889, in call_button
action = self._call_kw(model, method, args, {})
File "/opt/odoo/addons/web/controllers/main.py", line 877, in _call_kw
return call_kw(request.env[model], method, args, kwargs)
File "/opt/odoo/odoo/api.py", line 689, in call_kw
return call_kw_multi(method, model, args, kwargs)
File "/opt/odoo/odoo/api.py", line 680, in call_kw_multi
result = method(recs, *args, **kwargs)
File "/opt/odoo/odoo/addons/base/module/module.py", line 410, in button_immediate_install
return self._button_immediate_function(type(self).button_install)
File "/opt/odoo/odoo/addons/base/module/module.py", line 484, in _button_immediate_function
modules.registry.Registry.new(self._cr.dbname, update_module=True)
File "/opt/odoo/odoo/modules/registry.py", line 82, in new
odoo.modules.load_modules(registry._db, force_demo, status, update_module)
File "/opt/odoo/odoo/modules/loading.py", line 339, in load_modules
loaded_modules, update_module)
File "/opt/odoo/odoo/modules/loading.py", line 237, in load_marked_modules
loaded, processed = load_module_graph(cr, graph, progressdict, report=report, skip_modules=loaded_modules, perform_checks=perform_checks)
File "/opt/odoo/odoo/modules/loading.py", line 156, in load_module_graph
_load_data(cr, module_name, idref, mode, kind='data')
File "/opt/odoo/odoo/modules/loading.py", line 95, in _load_data
tools.convert_file(cr, module_name, filename, idref, mode, noupdate, kind, report)
File "/opt/odoo/odoo/tools/convert.py", line 845, in convert_file
convert_xml_import(cr, module, fp, idref, mode, noupdate, report)
File "/opt/odoo/odoo/tools/convert.py", line 915, in convert_xml_import
obj.parse(doc.getroot(), mode=mode)
File "/opt/odoo/odoo/tools/convert.py", line 796, in parse
self.parse(rec, mode)
File "/opt/odoo/odoo/tools/convert.py", line 799, in parse
self._tags[rec.tag](rec, de, mode=mode)
File "/opt/odoo/odoo/tools/convert.py", line 625, in _tag_record
model = self.env[rec_model]
File "/opt/odoo/odoo/api.py", line 760, in __getitem__
return self.registry[model_name]._browse((), self)
File "/opt/odoo/odoo/modules/registry.py", line 174, in __getitem__
return self.models[model_name]
ParseError: "ir.sequence.type" while parsing /home/walid/Bureau/model_x/views/Sequences.xml:3, near
<record id="seq_type_id" model="ir.sequence.type">
<field name="name">omega_sequence</field>
<field name="code">hr.employee</field>
</record>

我在我找到的所有网站上进行了搜索,他们给了我一些代码,但是每次我执行这段代码时,他都会给我上面的错误;请给我建议并谢谢。

最佳答案

ir.sequence.type 模型 has been removed在9.0版本中。您可以使用此代码:

<odoo>
<data noupdate="1">

<!-- ------*.xml file------- -->
<record id="seq_hr_employee" model="ir.sequence">
<field name="name">omega_sequencer</field>
<field name="code">hr.employee</field>
<field name="prefix">QO</field>
<field name="padding">5</field>
</record>

</data>
</odoo>
# ------------*.py file------------------
class omega(models.Model):
_name = 'omega.model'
_description = 'No Description for now !!'

sequence_id = fields.Char('Sequence', readonly=True)

@api.model
def create(self, vals):
seq = self.env['ir.sequence'].next_by_code('hr.employee') or '/'
vals['sequence_id'] = seq
return super(omega, self).create(vals)

关于odoo - 创建序列号odoo 10,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46435870/

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