java - 尝试读取用户输入时出现 NumberFormatException

Question

我是 Java 新手，正在编写一个程序来显示姓名、地址、电话号码和生日，其中姓名和电话号码是公开，生日是私有(private)，并且其他信息 protected 。

这是我的核心类(class):

public class newd {

    public int Name;
    public int Phone_no;
    protected String Address;
    protected int Age;
    private int Birth_day;

    void GetData() throws IOException
    {
        InputStreamReader IN = new InputStreamReader(System.in);
        BufferedReader BR = new BufferedReader(IN);

        System.out.print("Enter Name : ");
        String S1 = BR.readLine();
        Name = Integer.parseInt(S1);

        System.out.print("Enter Phone_no : ");
        String S2 = BR.readLine();
        Phone_no = Integer.parseInt(S2);

        System.out.print("Enter Address : ");
        String S3 = BR.readLine();
        Age = Integer.parseInt(S3);

        System.out.print("Enter Age : ");
        String S4 = BR.readLine();
        Age = Integer.parseInt(S4);

        System.out.print("Enter Birth_day : ");
        String S5 = BR.readLine();
        Birth_day = Integer.parseInt(S5);

    }

    void Display()
    {
        System.out.println("Name : " + Name);
        System.out.println("Phone No : " + Phone_no);
        System.out.println("Address : " + Address);
        System.out.println("Age : " + Age);
        System.out.println("Birth Day : " + Birth_day); 
    }

}

这是我的使用方法:

public class newdirectory {

    public static void main(String[] args) throws IOException {

        newd D = new newd();

        D.GetData();
        D.Display();

    }

}

当我编译程序时，它显示这个对话框。

Enter Name : kamrul
Exception in thread "main" java.lang.NumberFormatException: For input string: "kamrul"
    at java.lang.NumberFormatException.forInputString(Unknown Source)
    at java.lang.Integer.parseInt(Unknown Source)
    at java.lang.Integer.parseInt(Unknown Source)
    at newd.GetData(newd.java:21)
    at newdirectory.main(newdirectory.java:9)

谁能帮助我理解我做错了什么？

Answer 1

System.out.print("Enter Name : ");
String S1 = BR.readLine();
Name = Integer.parseInt(S1);

parseInt(...) 仅当传入的字符串可以解析为整数时才有效，否则将抛出 NumberFormatException。

引用this link here

对于你的情况，我想应该是:

public String Name;

你只需要这样做:

System.out.print("Enter Name : ");
Name = BR.readLine();

地址相同:

System.out.print("Enter Address : ");
Address = BR.readLine();