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php - 为什么这个验证码没有按预期工作?

转载 作者:行者123 更新时间:2023-12-01 22:31:20 26 4
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我有一个表单,并且 for m 的操作是同一页。我正在尝试:

  1. 在成功提交表单时显示感谢信息
  2. 在检测到错误的字段旁边显示错误消息
  3. 以上所有内容必须显示在同一页面中。

我的代码是:

<?php
$errors = array();
if (isset($_POST["Ask_the_Question"])) {
$guest_name = $_POST["guest_name"];
$title = $_POST["faq_title"];
$description = $_POST["faq_desc"];
$title = $_POST["faq_title"];

/* validation */
if (empty($guest_name)) {
$errors['guest_name'] = "Please type your name!";
}

if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';}

if(empty($errors)){
echo 'Thanks, We have received your feed back';
}
}

else {
?>
<form action="index.php" method="post" class="booking_reference">
<input type="text" name="guest_name" placeholder="Your Name" value="<?PHP if(!empty($errors)) { echo $guest_name;} ?>" />
<?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?>
<input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required />
<input type="text" name="faq_title" placeholder="FAQ Title"/>
<input type="text" name="faq_desc" placeholder="FAQ Description"/>
<input type="submit" name="Ask_the_Question" value="Ask the Question" />
</form>
<?php
}
?>

我限制了验证,只显示了这个问题的第一部分。

当我提交此表单时,如果没有任何错误,我将收到消息谢谢,我们已收到您的反馈这很好,并且按预期工作。

当存在错误/字段客人姓名 为空时,我在表单提交过程中收到消息错误!请检查以下有错误的字段。错误提示为红色。这也很好。

但是当我收到上述消息时,我的表单就消失了。为什么?我还想在字段旁边显示请输入您的姓名!

最佳答案

试试下面的代码。我已经删除了 else 部分并设置了 true/false 标志以检查是否有效。

<?php
$errors = array();
if (isset($_POST["Ask_the_Question"])) {
$guest_name = $_POST["guest_name"];
$title = $_POST["faq_title"];
$description = $_POST["faq_desc"];
$title = $_POST["faq_title"];

/* validation */
$chkValidate = "true";
if (empty($guest_name)) {
$errors['guest_name'] = "Please type your name!";
$chkValidate = "false";
}

if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';
$chkValidate = "false";
}

if($chkValidate == "true"){
echo 'Thanks, We have received your feed back';
}
}
?>
<form action="index.php" method="post" class="booking_reference">
<input type="text" name="guest_name" placeholder="Your Name" value="<?php if(!empty($errors) && $chkValidate != "false") { echo $guest_name;} ?>" />
<?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?>
<input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required />
<input type="text" name="faq_title" placeholder="FAQ Title"/>
<input type="text" name="faq_desc" placeholder="FAQ Description"/>
<input type="submit" name="Ask_the_Question" value="Ask the Question" />
</form>
<?php

?>

关于php - 为什么这个验证码没有按预期工作?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29449350/

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