java - 我可以将一堆 if 语句组合成一个对象吗？

Question

我有一个包含数千个单行句子的 ArrayList，我想搜索大约 50 个关键词。如果它包含这些关键字之一，我希望它将与该关键字对应的 double 值添加到数组中。检查完所有数组是否匹配后，我想对数组的总数进行求和。

目前我有与此类似的东西，除了数组列表和双变量列表要大得多:

import java.util.ArrayList;

public class searchArrayList {

public static void main(String[] args){


String subject2 = "The color of the ball is blue."; 
String subject3 = "The building is white.";
String subject4 = "Red is my favorite color.";  
String subject5 = "Black and blue are the team colors";



    ArrayList<Double> arrlist = new ArrayList<Double>();
    ArrayList<Double> difflist = new ArrayList<Double>();

    double Black = 10.1;
    double Blue = 1.6;
    double Red = 11.4;
    double White = 4.3;

    String[] subjectArray = {subject2,subject3,subject4,subject5};

    for (String subjects: subjectArray)
    {
        if (subjects.toUpperCase().contains("BLUE"));
        System.out.println(Blue+ "Blue ");
        arrlist.add(Blue);
        if (subjects.toUpperCase().contains("BLACK"));
        System.out.println(Black+" Black");
        arrlist.add(Black);
        if (subjects.toUpperCase().contains("WHITE"));
        System.out.println(White+" White");
        arrlist.add(White);
        if (subjects.toUpperCase().contains("RED"));
        System.out.println(Red+" Red");
        arrlist.add(Red);
    }
    System.out.println(sum(arrlist));
}

public static double sum(ArrayList<Double>arrlist)
{
  double result = 0;
  for (double number:arrlist)
  result += number;
  return result;
    }


   }

这满足了我的需要，但我想知道是否有更好或更直观的方法来做到这一点？我可以将 if 语句组合到单个对象/类中，然后调用该类来搜索数组吗？使用 switch 语句会更好吗？我尝试使用正则表达式进行搜索，但 .contains 似乎也同样有效。

Answer 1

只需使用包含关键字双关联的数组(或集合)，然后循环访问该数组:

public class Keyword {
    private String value;
    private double points;

    ...
}

private Keyword[] keywords = new Keyword[] {
    new Keyword("BLUE", 1.6),
    new Keyword("BLACK", 10.1),
    ...
}

for (String subject : subjectArray) {
    for (Keyword keyword : keywords) {
        if (subject.toUpperCase().contains(keyword.getValue())) {
            System.out.println(keyword.getPoints() + " " + keyword.getValue());
            arrlist.add(keyword.getPoints());
        }
    }
}