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java - 命令行参数导致 "main"线程中出现异常

转载 作者:行者123 更新时间:2023-12-01 22:28:17 25 4
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import java.util.*;

public class bubblesort {
public int input;
public int c;
public int d;
public int swap;
public int[] arr= new int[input];
Random rand = new Random();
Scanner in = new Scanner(System.in);

public static void main(String[] args) {
bubblesort b = new bubblesort();
Scanner in = new Scanner(System.in);
System.out.println("Ascending(1),Descending(2),Random(3)");
int arrayInput= in.nextInt();

if (arrayInput == 1) {
b.ascending(args);
}
else if (arrayInput == 2) {
b.descending(args);
}
else if (arrayInput == 3) {
b.random(args);
}
}


public void ascending(String[] args){
this.input = Integer.parseInt(args[0]);

for (c = 0; c < input; c++){
arr[c] = rand.nextInt(Integer.MAX_VALUE);
}

for (c = 0; c < ( input - 1 ); c++) {
for (d = 0; d < input - c - 1; d++) {
if (arr[d] > arr[d+1]){
swap = arr[d];
arr[d] = arr[d+1];
arr[d+1] = swap;
}
}
}
for (c = 0; c < input; c++)
System.out.println(arr[c]);

long startTime = System.nanoTime();
for (c = 0; c < input - 1; c++){
for (d =0; d < input - c -1 ; d++){
if (arr[d] > arr[d+1]){
swap = arr[d];
arr[d] = arr[d+1];
arr[d+1] = swap;
}
}
}
long endTime = System.nanoTime();
long estimatedTime = endTime - startTime;
System.out.println("Sorted list of numbers");
for (c = 0; c < input; c++)
System.out.println(arr[c]);
System.out.println("The time it takes to sort an descending array into an ascending array is "+estimatedTime+" nano seconds");
}
}

因此,当我编译这个文件(这不是我的整个文件)时,它会编译,只是当我尝试运行它时,它会给出异常:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at bubblesort.ascending(bubblesort.java:61)
at bubblesort.main(bubblesort.java:23)

我认为问题在于数组长度(或者我称之为“输入”)没有更改为命令行参数整数,因此输入保持为零。如果是这样,我该如何解决这个问题?

最佳答案

您无法初始化arr在解析用户输入之前。声明public int[] arr= new int[input];结果是一个大小为 0 的数组,因此任何访问它的尝试都会抛出异常。解析数组长度后,尝试在 main 中初始化数组。

关于java - 命令行参数导致 "main"线程中出现异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28306149/

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