go - 如何将复杂的字符串输入转换为map [string] [] string？

Question

我想要一个字符串，并将其转换为map[string][]string。到目前为止，我已经能够将字符串转换为map [string] string，如下所示:

package main

import(
 "fmt"
 "strings"
)

func main(){
    var m map[string]string
    var ss []string

    s := "Owner.RefObjectName: Owner1, Owner2, Owner3&ScheduleState:State1, State2"
    ss = strings.Split(s, "&")

    m = make(map[string]string)
    for _, pair := range ss {
        z := strings.Split(pair, ":")
        m[z[0]] = z[1]
    }
    fmt.Println(m)
}

这给了我一个使用字符串键和字符串值的映射，如下所示:

map[Owner.RefObjectName: Owner1, Owner2, Owner3 ScheduleState:State1, State2]

但是，我需要将字符串值转换为字符串 slice ，因为我需要自己引用诸如Owner1之类的单个项。简而言之，我希望最终 map 看起来像这样:

m := map[string][]string{
        "Owner.RefObjectName": {"Owner1", "Owner2", "Owner3"},
        "ScheduleState": {"State1", "State2"},
    }

其中Owner1 Owner2 Owner3不在单个字符串中，而是在字符串 slice 中。

Answer 1

用逗号进一步分割字符串:

    var m map[string][]string
    // ...
    m = make(map[string][]string)
    for _, pair := range ss {
        obj := strings.Split(pair, ":")
        key := obj[0]
        v := strings.Split(obj[1], ",")
        m[key] = v
    }