java - Play Framework 。如何使用外部端点上传照片？

Question

如何使用 playframework 中的 URL 上传照片？我当时是这样想的:

URL url = new URL("http://www.google.ru/intl/en_com/images/logo_plain.png");
BufferedImage img = ImageIO.read(url);
File newFile = new File("google.png");
ImageIO.write(img, "png", newFile);

但也许还有另一种方法。最后我必须获取文件和文件名。

Controller 示例:

public static Result uploadPhoto(String urlPhoto){ 
    Url url = new Url(urlPhoto); //doSomething 
    //get a picture and write to a temporary file
    File tempPhoto = myUploadPhoto;
    uploadFile(tempPhoto); // Here we make a copy of the file and save it to the file system.
    return ok('something');
}

Answer 1

要获取该照片，您可以使用 play WS API，后面的代码是从处理大型响应部分中的 play 文档中提取的示例，我建议您阅读完整文档 here

final Promise<File> filePromise = WS.url(url).get().map(
        new Function<WSResponse, File>() {
            public File apply(WSResponse response) throws Throwable {

                InputStream inputStream = null;
                OutputStream outputStream = null;
                try {
                    inputStream = response.getBodyAsStream();

                    // write the inputStream to a File
                    final File file = new File("/tmp/response.txt");
                    outputStream = new FileOutputStream(file);

                    int read = 0;
                    byte[] buffer = new byte[1024];

                    while ((read = inputStream.read(buffer)) != -1) {
                        outputStream.write(buffer, 0, read);
                    }

                    return file;
                } catch (IOException e) {
                    throw e;
                } finally {
                    if (inputStream != null) {inputStream.close();}
                    if (outputStream != null) {outputStream.close();}
                }

            }
        }
);

网址是:

String url = "http://www.google.ru/intl/en_com/images/logo_plain.png"

这是大文件 Play 文档中建议的:

*

When you are downloading a large file or document, WS allows you to get the response body as an InputStream so you can process the data without loading the entire content into memory at once.

*