java - Java 中的 "Guess the number"

Question

我们打算用 java 创建一个程序，其中计算机随机猜测 1-100 之间的数字，并允许用户猜测该数字。如果该数字低于随机数，程序应该说:较低!对于更高，程序应该说:更高!如果用户猜对了数字，它应该说恭喜你在 X 次尝试中猜对了正确的数字，这就是我到目前为止所拥有的，当我在 cmd 中执行时，它只是垃圾邮件更高或更低，我需要帮助解决这个问题。

import java.util.Scanner;
import java.util.Random;

public class GuessingGame{

    public static void main(String[] args) {

        int random, guess, attempts;
        Scanner keyboard = new Scanner(System.in);
        Random generator = new Random();
        random = generator.nextInt(100) + 1;
        attempts = 1; 

        System.out.print("I am thinking of a number between 0 and 100, what do you think it is?");

        guess = keyboard.nextInt(); 
        while (guess != random) {
            if (guess > random) {
                System.out.print("Lower!");
                attempts += 1; 
            }
            else {
                System.out.print("Higher!");
                attempts +=1;
            } 
        }

        System.out.print(random + "is the correct answer and it took you" + attempts + "attempts to guess it!");

    }        
}

Answer 1

您只读取输入一次，然后永远循环(您在循环之外读取输入)。

尝试读取循环内的输入并使用do-while循环:

guess = 0;        

do {
    guess = keyboard.nextInt(); 

    if (guess > random) {
        System.out.print("Lower!");
        attempts += 1; 
    } else {
        System.out.print("Higher!");
        attempts +=1;
    }
 } while (guess != random);