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java - 如何使用 JPA 提高更新数据的性能

转载 作者:行者123 更新时间:2023-12-01 22:17:53 24 4
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我正在使用 EJB 和容器管理的 EM(为了进行本地测试,我在此处创建它们)。我有一个要求,我需要根据某些条件更新数据库,我的问题是更新需要很长时间,如何减少它?

我尝试了两种方法1> 更新查询2> 更新实体

如果我犯了任何错误,或者存在任何其他方法,请告诉我。

注意:更新代码如下

    public class Test {
private static final int OaOnaccount = 0;
private static final int ArrayList = 0;
private static EntityManagerFactory emf;
private static EntityManager em;
static int TEST_SIZE = 20000/4;

public static void main(String[] args) {
// createBulk();
createUpdateQuery();
// update();

}

private static void createUpdateQuery() {
long st = System.currentTimeMillis();
emf = Persistence.createEntityManagerFactory("Jpa");
em = emf.createEntityManager();
System.out.println("---- createUpdateQuery ---");
EntityTransaction tx = em.getTransaction();
Query query = em.createQuery("SELECT p FROM OaOnaccount p");
tx.begin();
java.util.Vector<OaOnaccount> list = (java.util.Vector<OaOnaccount>) query.getResultList();
for (int i = 0; i < list.size(); i++) {
String m = 1000000 + (i / 20) + "";
query = em
.createQuery("UPDATE OaOnaccount p SET p.status='COMPLETED', p.billingDoc='12112ABCS' WHERE p.crDrIndicator='H' AND p.status ='OPEN' AND p.documentNumber="+ m);
query.executeUpdate();
}

em.flush();
tx.commit();

long et = System.currentTimeMillis();

System.out.println("Test.createUpdateQuery() Time " + (et - st));

}

private static void update() {

long st = System.currentTimeMillis();
emf = Persistence.createEntityManagerFactory("Jpa");
em = emf.createEntityManager();
System.out.println("---- update ---");
EntityTransaction tx = em.getTransaction();
Query query = em.createQuery("SELECT p FROM OaOnaccount p");
tx.begin();

java.util.Vector<OaOnaccount> list = (java.util.Vector<OaOnaccount>) query
.getResultList();
for (int i = 0; i < list.size(); i++) {
String m = 1000000 + (i / 20) + "";
query = em
.createQuery("SELECT p FROM OaOnaccount p WHERE p.crDrIndicator='H' AND p.status ='OPEN' AND p.documentNumber="
+ m);
java.util.Vector<OaOnaccount> listEn = (java.util.Vector<OaOnaccount>) query
.getResultList();
for (int j = 0; j < listEn.size(); j++) {
listEn.get(j).setBillingDoc("12112ABCS");
listEn.get(j).setStatus("COMPLETED");
}
}

em.flush();
tx.commit();

long et = System.currentTimeMillis();

System.out.println("Test.Update() Time " + (et - st));

}

public static void createBulk() {
long st = System.currentTimeMillis();
emf = Persistence.createEntityManagerFactory("Jpa");
em = emf.createEntityManager();
System.out.println("-------");
EntityTransaction tx = em.getTransaction();
tx.begin();

for (int i = 0; i < TEST_SIZE; i++) {
OaOnaccount entity = new OaOnaccount();
entity.setId("ID-" + i);
entity.setCrDrIndicator(i % 2 == 0 ? "H" : "S");
entity.setDocumentNumber(1000000 + (i / 20) + "");
entity.setAssignment(89000000 + (i / 27) + "");
entity.setStatus("OPEN");
em.persist(entity);
}
em.flush();
tx.commit();

long et = System.currentTimeMillis();

System.out.println("Test.createBulk() Time " + (et - st));

}

}

最佳答案

你应该每n次迭代执行em.flush()。例如,如果 n- 太低,则数据库交互次数会增加,因此执行代码会很慢。如果 n- 太高,内存中驻留的对象就会过多,因此交换次数会增多,从而导致代码执行速度变慢。请适度选择n值并应用。我尝试更新 240 万条记录,我遇到了同样的问题。

      for (int i = 0; i < list.size(); i++) {
String m = 1000000 + (i / 20) + "";
query = em
.createQuery("UPDATE OaOnaccount p SET p.status='COMPLETED', p.billingDoc='12112ABCS' WHERE p.crDrIndicator='H' AND p.status ='OPEN' AND p.documentNumber="+ m);
query.executeUpdate();
if(i%100==0){// 100 to just to show example-- % operation is costly. you can use better logic to flush. frequent flushing is necessary
em.flush();
}
}

关于java - 如何使用 JPA 提高更新数据的性能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30603328/

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