r - 如何在 car::scatter3d 图中显示坐标网格

Question

只需运行以下代码即可。我想显示坐标网格，但没有任何反应:

df_runtime <- data.frame(x = c(0L, 20L), 
                         y = c(0L, 10L), 
                         z = c(0L, 50L), stringsAsFactors = FALSE)

car::scatter3d(x = df_runtime$x,
               y = df_runtime$y,
               z = df_runtime$z,
               xlab = "x", ylab = "x", zlab = "z", 
               surface = FALSE, grid = TRUE)

从文档??car::scatter3d我意识到

plot grid lines on the regression surface(s) (TRUE or FALSE).

因此，grid 参数不是我想要的。 有没有办法获得坐标网格？对我来说，这作为眼睛的指南非常有用。

<小时/>

Carles 输入后编辑:

我想保留交互式图表 - 这就是我寻找 car::scatter3d 解决方案的原因。如果您不需要这个，scatterplot3d 和 FactoClass 的组合非常好。以下以非交互方式工作:

scatterplot3d::scatterplot3d(
  df_runtime$x,
  df_runtime$y,
  df_runtime$z,
  color = "blue", pch = 19, # filled blue circles
  # type = "h",             # lines to the horizontal plane
  main = "Title",
  xlab = "x",
  ylab = "y",
  zlab = "z",
  angle = 35,
  grid = FALSE)
FactoClass::addgrids3d(df_runtime$x,
                       df_runtime$y,
                       df_runtime$z,
                       angle = 35,
                       grid = c("xy", "xz", "yz"))

Answer 1

如果您想要带有网格的交互式绘图，plotly 是另一种解决方案:

df_runtime <- data.frame(x = c(0L, 20L), 
                         y = c(0L, 10L), 
                         z = c(0L, 50L), stringsAsFactors = FALSE)

plotly::plot_ly(df_runtime, 
                     x = ~x, 
                     y = ~y, 
                     z = ~z,
                type = 'scatter3d',
                mode = 'markers')