java - 选择: but not including :之后 ""(含)内的所有文本

Question

aa: {
        one: "hello",
        two: "good",
        three: "bye",
        four: "tomorrow",

    },
    "bb": {
        "1": "a quick fox",
        "2": "a slow bird",
        "3": "a smart dog",
        "4": "a wilf flowert",

我的数据类似于上面我想要选择的是 : 右侧“”内的所有文本，其中包括“”标记

我得到的是

: ("(.*?)")

但它选择了 : ，这也不是我想要的。

Answer 1

如果必须使用正则表达式，可以尝试Matcher.group()方法，如发现here .

public class TestClass {
    public static void main(String[] args) {
        String input = "aa: {\n" +
                "    one: \"hello\",\n" +
                "    two: \"good\",\n" +
                "    three: \"bye\",\n" +
                "    four: \"tomorrow\",\n" +
                "  },\n" +
                "  \"bb\": {\n" +
                "    \"1\": \"a quick fox\",\n" +
                "    \"2\": \"a slow bird\",\n" +
                "    \"3\": \"a smart dog\",\n" +
                "    \"4\": \"a wilf flowert\",\n";
        // the actual code you need
        Pattern pattern = Pattern.compile("(: )(\".+\")");
        Matcher match = pattern.matcher(input);
        while (match.find()) {
            // here you go, only the value without the :
            String value = match.group(2);
            System.out.println("Found one = " + value);
        }
    }
}

这对我来说结果如下:

Found one = "hello"
Found one = "good"
Found one = "bye"
Found one = "tomorrow"
Found one = "a quick fox"
Found one = "a slow bird"
Found one = "a smart dog"
Found one = "a wilf flowert"