go - 使用http.NewRequest进行测试时，为什么我的请求URL解析不正确？

Question

当我使用curl测试我的/ health /端点时，一切都按预期工作:curl localhost:8080/health/my_id返回my_id。
但是，当我运行测试时，处理程序无法从参数中提取ID。
我应该如何从测试中构建查询以实现这一目标？
HealthTest

 12 func TestHealth(t *testing.T) {
 13
 14         // Initialize a new httptest.ResponseRecorder.
 15         rr := httptest.NewRecorder()
 16
 17         // Initialize a new dummy http.Request.
 18         r, err := http.NewRequest(http.MethodGet, "/health/my_id", nil)
 19         if err != nil {
 20                 t.Fatal(err)
 21         }
 22
 23         // Call the handler function, passing in the
 24         // httptest.ResponseRecorder and http.Request.
 25         handler.HandleHealth(rr, r)
 26
 27         // Call the Result() method on the http.ResponseRecorder to get the
 28         // http.Response generated by the handler.
 29         rs := rr.Result()
 30
 31         // We can then examine the http.Response to check that the status code // written by the handler was 200.
 32         if rs.StatusCode != http.StatusOK {
 33                 t.Errorf("want %d; got %d", http.StatusOK, rs.StatusCode)
 34         }
 35
 36         // And we can check that the response body written by the handler
 37         defer rs.Body.Close()
 38         body, err := ioutil.ReadAll(rs.Body)
 39         if err != nil {
 40                 t.Fatal(err)
 41         }
 42
 43         want := "my_id"
 44         got := string(body)
 45         if got != want {
 46                 t.Errorf("want body to equal %q. Got: %q", want, got)
 47         }
 48 }

运行该测试会导致:

internal/handler/health/handler_test.go|46| want body to equal "my_id". Got: ""

HealthHandlers

   23 func (h *Handler) HandleHealth(w http.ResponseWriter, r *http.Request) {
   24         id := chi.URLParam(r, "id")
   25         log.Println("ID: ", id)
   26         render.PlainText(w, r, id)
   27 }
   28

   29 func RegisterRoutes(router *chi.Mux, handler *Handler) {
   30         router.Get("/health/{id}", handler.HandleHealth)
   31 }

Answer 1

chi库是处理通配符URL的库。但是，您可以通过直接调用HandleHealth绕过测试中的chi。
如果要让chi针对RegisterRoutes方法中提供的通配符处理请求，则显然需要在测试中实际调用RegisterRoutes。
这样做需要稍微更改测试结构。而不是:

    handler.HandleHealth(rr, r)

您将需要以下内容:

    chi := chi.NewMux()
    RegisterRoutes(chi, handler)
    chi.ServeHTTP(rr, r)