PHP 比较两个字符串中的一个字符不同，通配符方法

Question

需要比较两个字符串以获得一个 PAIR，唯一的条件是只有第 5 个字符必须不同...在 mysql 中，可以通过 INBXOLC800Y = INBX_LC800Y (使用“_”通配符)来实现，但如何在 PHP 中执行此操作...这是我到目前为止的代码，但我想可能有更智能和/或最短的方法???

$first_sku_full  = "INBXOLC800Y"; // with O
$second_sku_full = "INBXTLC800Y"; // with T

$first_sku_first_part= substr($first_sku_full,0,4); //gives first 4 characters INBX
$second_sku_first_part= substr($second_sku_full,0,4); //gives first 4 characters INBX

if($first_sku_first_part == $second_sku_first_part){  // matching first 4 characters

    $first_sku_last_part= substr($first_sku_full, 5);   // gives 6th onward characters i.e, LC800Y
    $second_sku_last_part= substr($second_sku_full, 5); // gives 6th onward characters i.e, LC800Y
    if ( $first_sku_last_part == $second_sku_last_part ) { // matching 6th and onward characters
        if ( $first_sku_full != $second_sku_full ) { // matching full strings
            echo "first and second sku is a pair <br/>";
        }else{
            echo "NOT a pair , both SKUs are same <br/>";
        }
    }else{
        echo "NOT a pair , last part of string not matched $first_sku_last_part vs $second_sku_last_part <br/>";
    }
}else{
    echo "NOT a pair , first part of string not matched $first_sku_first_part vs $second_sku_first_part<br/>";

}

Answer 1

试试这个功能:

function isOnlyThe5thCharacterDifferent($inp1,$inp2)
{
    if ($inp1[4]!=$inp2[4])
    {
        $inp1[4]=$inp2[4];

        return ($inp1==$inp2);
    }

    return false;
}

查看实际效果:https://3v4l.org/fn2sG