python - 类型错误 : unsupported operand type(s) for |: 'str' and 'bool'

Question

我有具有不同列的数据框用户。我的目标是添加 [uses_name] 列，当密码与每个用户的名字或姓氏相同时，该列应为 True。

例如，十二行中的 [user_name] 包含 milford.hubbard。那么 [uses_name] 将为 True，因为 [password] 和 [last_name] 相同。

为此，我使用正则表达式创建了两列 [first_name] 和 [last_name]。创建 [uses_name] 时，我在使用 | 运算符时遇到问题。我在 pandas 文档中阅读了有关 boolean 索引的更多内容，但没有找到答案。

我的代码:

import pandas as pd

users = pd.read_csv('datasets/users.csv')

# Extracting first and last names into their own columns

users['first_name'] = users['user_name'].str.extract(r'(^\w+)', expand=False)

users['last_name'] = users['user_name'].str.extract(r'(\w+$)', expand=False)

# Flagging the users with passwords that matches their names

users['uses_name'] = users['password'].isin(users['first_name'] | users['last_name'])

# Counting and printing the number of users using names as passwords

print(users['uses_name'].count())

# Taking a look at the 12 first rows

print(users.head(12))

当我尝试编译它时，出现错误:

TypeError: unsupported operand type(s) for |: 'str' and 'bool'

users 数据框中的前 12 行，其中创建了 first_name 和 last_name 列:

id          user_name            password   first_name  last_name
0    1    vance.jennings          joobheco      vance    jennings
1    2    consuelo.eaton        0869347314   consuelo       eaton
2    3   mitchel.perkins        fabypotter    mitchel     perkins
3    4    odessa.vaughan         aharney88     odessa     vaughan
2    3   mitchel.perkins        fabypotter    mitchel     perkins
3    4    odessa.vaughan         aharney88     odessa     vaughan
4    5    araceli.wilder        acecdn3000    araceli      wilder
5    6  shawn.harrington           5278049      shawn  harrington
6    7        evelyn.gay            master     evelyn         gay
7    8       noreen.hale            murphy     noreen        hale
8    9       gladys.ward           lwsves2     gladys        ward
9   10   brant.zimmerman  1190KAREN5572497      brant   zimmerman
10  11     leanna.abbott          aivlys24     leanna      abbott
11  12   milford.hubbard           hubbard    milford     hubbard

Answer 1

这有效:

users['uses_name']= (users['password']==users['first_name'] )| (users['password']==users['last_name'])