scala - 方法映射的参数太多 : (apply: (String, models.Address) => R)(unapply : R => Option[(String, models.Address)])play.api.data.Mapping[R]

Question

我有两个这样的案例类。

case class Company(name: String, address: Address)
case class Address(address1: String, address2: String, 
                   city: String, state: String, 
                   zip:String, country: String)

在我的 Application.scala 中，我定义了以下内容。

[1]. val companyForm = Form(of(Company.apply _, Company.unapply _)(
    "name" -> text,
    "address" -> mapping(
        "address1" -> nonEmptyText,
        "address2" -> text,
        "city" -> nonEmptyText,
        "state" -> nonEmptyText,
        "zip" -> nonEmptyText,
        "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )
)

[2]. val companyForm = Form(mapping(
    "name" -> text,
    "address" -> mapping(
        "address1" -> nonEmptyText,
        "address2" -> text,
        "city" -> nonEmptyText,
        "state" -> nonEmptyText,
        "zip" -> nonEmptyText,
        "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )(Company.apply, Company.unapply)
)

现在 [1] 对我有用，但是当我尝试将其转换为 [2] 时，它给了我以下错误:

方法映射的参数太多:(apply: (String, models.Address) => R)(unapply: R => Option[(String, models.Address)])play.api.data.Mapping[R ].

请告诉我我做错了什么。提前致谢。

Answer 1

由于 method of() 已被废弃，您的表单必须如下所示:

     val companyForm = Form(
    mapping(
    "name" -> text,
    "address" -> mapping(
      "address1" -> nonEmptyText,
      "address2" -> text,
      "city" -> nonEmptyText,
      "state" -> nonEmptyText,
      "zip" -> nonEmptyText,
      "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )(Company.apply)(Company.unapply)
  )

所以你的问题出在下面的语法中 Company.Apply 和 Company.unapply 方法