java - SAXException=XML 文档结构必须在同一实体内开始和结束

Question

有人可以告诉我为什么会出现这个解析错误吗？ XML 对我来说看起来不错。它因 SAXException=XML 文档结构必须在同一实体内开始和结束而失败。在这一行:

Document doc = builder.parse(inputSource);  //fails here

这是代码:

        String soapIn = "<?xml version='1.0' encoding='UTF-8' ?>\n" +
"<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:vid=\"http://videocontrollerchannelmap.queryservice.vcwh.oss.my.company.com/\">\n" +
"   <soapenv:Header/>\n" +
"   <soapenv:Body>\n" +
"      <vid:getInneoquestChannelMap>\n" +
"         <appkey>ONE_CONTROLLER</appkey>\n" +
"         <forceUpdate>true</forceUpdate>\n" +
"      </vid:getInneoquestChannelMap>\n" +
"   </soapenv:Body>\n" +
"</soapenv:Envelope";
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setNamespaceAware(true);
        SOAPMessage newMsg = null;
        try {
            DocumentBuilder builder = factory.newDocumentBuilder();
            InputSource inputSource = new InputSource(new StringReader(soapIn));
            Document doc = builder.parse(inputSource);  //fails here
            DOMSource domSource = new DOMSource(doc);

Answer 1

您缺少>上"</soapenv:Envelope" .