Java异常处理循环错误

Question

我想出了一切办法来寻求帮助

当我在尝试 1/4 处输入字母时，它工作正常并继续，但是一旦我在尝试 2/4 处输入字母，它只会打印消息并且程序停止。还有关于#2的任何提示，我只能想到 if(guess>=4 &&guess<=16) else 语句(不确定这是否正确)

当我执行代码时 -

Guess a number between 1 and 16.

Attempt 1 of 4: 8

You guessed 8

Too Low! 

Attempt 2 of 4: a

Please enter an integer between 4-16     

之后无法输入任何内容

问题:如果用户输入 a，我必须创建异常处理程序

1) 非数字输入

2)输入超出范围

3)必须保留当前猜测金额

import java.util.InputMismatchException;
import java.util.Random;
import java.util.Scanner;

public class GuessingGame {

static final int limit = 4;
static final int maxInteger = 16;

public static void main(String[] args) {

Random rand = new Random();
int target = rand.nextInt(maxInteger) + 1;
int x = 1;

    do{
    try{
        Scanner input = new Scanner(System.in);
        System.out.printf("Guess a number between 1 and %d.\n", maxInteger);


    int attempts = 1;
    while (attempts <= limit) {
        System.out.printf("Attempt %d of %d: ", attempts, limit);


        int guess = input.nextInt();
        System.out.printf("You guessed %d\n", guess);

        if(guess > target) {
        System.out.printf("Too High! \n");

        }
        else if(guess == target){

        System.out.printf("The answer is %d, You win!", guess);
            attempts = 20;

        }
        else{
        System.out.printf("Too Low! \n");

        }

        attempts+=1;
        x = 2;
    }
    if(attempts==5){
    System.out.println("You lose!");
    }
    }
    catch(InputMismatchException e){
        System.out.printf("Please enter an integer between 4-16");
        continue;


    }
    }while(x == 1);
}
}

Answer 1

您正在检查while(x == 1);在外循环和内循环中，您增加了 x 的值通过这样做x = 2; 。这将打破条件，你将从外部 while 中出来。循环。

您应该为外部 while 设置有效条件如果您想继续，请循环。尝试类似 while(x < 5);

您的代码应如下所示:

do {
    try {
        ...
        /* Inner While */
        while() {}
        ...
    } catch () {
        /* Exception Handling */
        ...
    }
} while(x < 5); /* Decide a valid condition */