java - 当空格数量未知时，替代正向回顾

Question

我的replacerRegex是

("schedulingCancelModal": \{\s*? "title": ")(.+?)(?=")

正在获取正确的值，即 valueToBePicked:

但是如何才能使 ("schedulingCancelModal":\{\s*? "title": ") 不像正向lookbehind那样包含在结果中？

到目前为止我的 Java 代码:

Pattern replacerPattern = Pattern.compile(replacerRegex);
Matcher matcher = replacerPattern.matcher(value);

while (matcher.find()) {
    String valueToBePicked = matcher.group();
}

Answer 1

您只需选择 matcher.group(2) 即可获得第二个捕获组的内容。例如:

    String replacerRegex = "(\"schedulingCancelModal\": \\{\\s*? \"title\": \")(.+?)(?=\")";
    String value = "\"valueToBePicked\": \"schedulingCancelModal\": {\n \"title\": \"Are you sure you want to leave scheduling?\", ... }";
    Pattern replacerPattern = Pattern.compile(replacerRegex);
    Matcher matcher = replacerPattern.matcher(value);

    while (matcher.find()) {
        String valueToBePicked = matcher.group(2);
        System.out.println(valueToBePicked);
    }        

输出:

Are you sure you want to leave scheduling?

Demo on rextester