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winapi - 在 Windows 上播放任意声音?

转载 作者:行者123 更新时间:2023-12-01 21:43:59 29 4
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如何在 Windows(32 位和 64 位,最高 Windows 7)上本地播放具有给定振幅和给定频率组成(例如,由 2 kHz 和 3 kHz 频率组成)的声音?

( native 是指不使用外部库。)

我相信这需要 waveOutWrite方法,但我不知道它是如何工作的。

最佳答案

我有一些工作......

#define _USE_MATH_DEFINES 1
#include <math.h>
#include <stdio.h>
#include <tchar.h>

#include <windows.h>
#include <mmreg.h>
#include <complex>

#pragma comment(lib, "Winmm.lib")

MMRESULT play(float nSeconds,
float signal(float timeInSeconds, unsigned short channel, void *context),
void *context = NULL, unsigned long samplesPerSecond = 48000)
{
UINT timePeriod = 1;

MMRESULT mmresult = MMSYSERR_NOERROR;
WAVEFORMATEX waveFormat = {0};
waveFormat.cbSize = 0;
waveFormat.wFormatTag = WAVE_FORMAT_IEEE_FLOAT;
waveFormat.nChannels = 2;
waveFormat.nSamplesPerSec = samplesPerSecond;
const size_t nBuffer =
(size_t)(nSeconds * waveFormat.nChannels * waveFormat.nSamplesPerSec);
float *buffer;
waveFormat.wBitsPerSample = CHAR_BIT * sizeof(buffer[0]);
waveFormat.nBlockAlign =
waveFormat.nChannels * waveFormat.wBitsPerSample / CHAR_BIT;
waveFormat.nAvgBytesPerSec =
waveFormat.nSamplesPerSec * waveFormat.nBlockAlign;

buffer = (float *)calloc(nBuffer, sizeof(*buffer));
__try
{
for (size_t i = 0; i < nBuffer; i += waveFormat.nChannels)
for (unsigned short j = 0; j < waveFormat.nChannels; j++)
buffer[i+j] = signal((i+j) * nSeconds / nBuffer, j, context);
HWAVEOUT hWavOut = NULL;
mmresult = waveOutOpen(&hWavOut, WAVE_MAPPER,
&waveFormat, NULL, NULL, CALLBACK_NULL);
if (mmresult == MMSYSERR_NOERROR)
{
__try
{
timeBeginPeriod(timePeriod);
__try
{
WAVEHDR hdr = {0};
hdr.dwBufferLength =
(ULONG)(nBuffer * sizeof(buffer[0]));
hdr.lpData = (LPSTR)&buffer[0];
mmresult = waveOutPrepareHeader(hWavOut,
&hdr, sizeof(hdr));
if (mmresult == MMSYSERR_NOERROR)
{
__try
{
ULONG start = GetTickCount();
mmresult =
waveOutWrite(hWavOut, &hdr, sizeof(hdr));
Sleep((ULONG)(1000 * nSeconds
- (GetTickCount() - start)));
}
__finally
{ waveOutUnprepareHeader(hWavOut, &hdr, sizeof(hdr)); }
}
}
__finally { timeEndPeriod(timePeriod); }
}
__finally { waveOutClose(hWavOut); }
}
}
__finally { free(buffer); }
return mmresult;
}

// Triangle wave generator
float triangle(float timeInSeconds, unsigned short channel, void *context)
{
const float frequency = *(const float *)context;
const float angle = (float)(frequency * 2 * M_PI * timeInSeconds);
switch (channel)
{
case 0: return (float)asin(sin(angle + 0 * M_PI / 2));
default: return (float)asin(sin(angle + 1 * M_PI / 2));
}
}

// Pure tone generator
float pure(float timeInSeconds, unsigned short channel, void *context)
{
const float frequency = *(const float *)context;
const float angle = (float)(frequency * 2 * M_PI * timeInSeconds);
switch (channel)
{
case 0: return (float)sin(angle + 0 * M_PI / 2);
default: return (float)sin(angle + 1 * M_PI / 2);
}
}

int _tmain(int argc, _TCHAR* argv[])
{
float frequency = 2 * 261.626F;
play(1, pure, &frequency);
return 0;
}

关于winapi - 在 Windows 上播放任意声音?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5814869/

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