reactjs - 如何在 React.js 中将图像上传到 Firebase 存储并同时将 URL 上传到 Firestore？

Question

我是 React.js 的新手，我正在尝试将图像上传到 Firebase 存储，并且在成功上传后我试图同时将 downloadURL 推送到 Firestore。怎么做？这是上传图片正常但 firestore 不工作的代码。

    import React, {useState, Component} from 'react';
    import firebase from "../firebase";

    const storage = firebase.storage();

    class ImageUpload extends Component {
      constructor(props) {
        super(props);
        this.state = {
          image: null,
          url: '',
          progress: 0
        }
        this.handleChange = this
          .handleChange
          .bind(this);
          this.handleUpload = this.handleUpload.bind(this);
      }
      handleChange = e => {
        if (e.target.files[0]) {
          const image = e.target.files[0];
          this.setState(() => ({image}));
        }
      }
      handleUpload = () => {
          const {image} = this.state;
          const uploadTask = storage.ref(`images/${image.name}`).put(image);
          uploadTask.on('state_changed',
          (snapshot) => {
            // progrss function ....
            const progress = Math.round((snapshot.bytesTransferred / snapshot.totalBytes) * 100);
            this.setState({progress});
          },
          (error) => {
               // error function ....
            console.log(error);
          },
        () => {
            // complete function ....
            storage.ref('images').child(image.name).getDownloadURL().then(url => {
                console.log(url);
                this.setState({url});

//*************************** 这部分不工作(开始)*********** **********************

                const [imgURL, setImgURL] = useState('')

                firebase
                .firestore()
                .collection('notes')
                .add({
                  imgURL
                })
                .then(() => {
                  setImgURL('')
                })

//****************************** 这部分不工作(完) ******* *************************

            })
        });
      }
      render() {

        return (
          <div>
          <progress value={this.state.progress} max="100"/>
          <br/>
            <input type="file" onChange={this.handleChange}/>
            <button onClick={this.handleUpload}>Upload</button>
            <br/>

            <img src={this.state.url || 'http://via.placeholder.com/400x300'} alt="Uploaded images" height="300" width="400"/>
          </div>
        )
      }
    }
    export default ImageUpload;

Answer 1

要将下载URL写入数据库，你不需要将其存储在状态中。您可以直接在 then 处理程序中将其写入数据库:

storage.ref('images').child(image.name).getDownloadURL().then(url => {
    firebase
    .firestore()
    .collection('notes')
    .add({
      imgURL: url
    })
    .then(() => {
      setImgURL('')
    })
});