java - 启动画面结束后应用程序不断崩溃

Question

这个问题已经有答案了:

"ArrayAdapter requires the resource ID to be a TextView" XML problems (4 个回答)

Unfortunately MyApp has stopped. How can I solve this? (23 个回答)

已关闭 3 年前。

我目前正在开发一个应用程序，其中包含带有声音的启动屏幕。启动画面完成后，我希望它能够进入我的主菜单。我遇到的问题是播放声音后它不断崩溃。我尝试过以不同的方式处理具有相同问题的其他线程，但它在启动屏幕结束时不断崩溃。

编辑:当我运行应用程序时，我的事件日志显示应用程序成功并且没有发现错误。我运行了调试器，它显示

E/ArrayAdapter: You must supply a resource ID for a TextView
D/AndroidRuntime: Shutting down VM
E/AndroidRuntime: FATAL EXCEPTION: main
    Process: com.example.finalproject, PID: 12755
    java.lang.IllegalStateException: ArrayAdapter requires the resource ID to be a TextView

Caused by: java.lang.ClassCastException: android.widget.RelativeLayout cannot be cast to android.widget.TextView
        at android.widget.ArrayAdapter.createViewFromResource(ArrayAdapter.java:388)

我相信一定是我的 MainActivity 引起了问题。

我的启动代码:

public class SplashActivity extends AppCompatActivity {

    MediaPlayer ourSound;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_splash);

        Thread timer = new Thread(){
            @Override
            public void run(){
                try {
                    ourSound = MediaPlayer.create(SplashActivity.this, R.raw.splashsound);
                    ourSound.start();
                    sleep(4000);
                } catch (InterruptedException e){

                } finally {
                    Intent i = new Intent(SplashActivity.this, MainActivity.class);
                    startActivity(i);
                } // end finally
            } // end run
        };
        timer.start();
    } // end onCreate
    @Override

    protected void onPause(){
        super.onPause();
        ourSound.release();

    } // end onPause
} // end SplashActivity

我的主要 Activity 代码:

public class MainActivity extends ListActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        //setContentView(R.layout.activity_main);
        String[] mainMenu = {"Websites", "Directions", "Scheduling", "Photos"};
        setListAdapter(new ArrayAdapter<String>(this, R.layout.activity_main, mainMenu));
    } // end onCreate

    protected void onListItemClick(ListView l, View v, int position, long id) {
        switch (position) {
            case 0:
                startActivity(new Intent(MainActivity.this, Websites.class));
                break;
            case 1:
                startActivity(new Intent(MainActivity.this, Directions.class));
                break;
            case 2:
                startActivity(new Intent(MainActivity.this, Scheduling.class));
                break;
            case 3:
                startActivity(new Intent(MainActivity.this, Photos.class));
                break;
        } // end switch
    }// end onListItemClick
} // end MainActivity

Answer 1

这应该适合你

setListAdapter(new ArrayAdapter(this, R.layout.activity_main, mainMenu));

问题出在 R.layout.activity_main 上。应该是R.layout.simple_list_item