java - 如何检查值是否正确？

Question

在我的 setValue 中，我在测试类中测试了不正确的错误，在我的测试类中 setValue 是 0，因此它预计为 00，但它在终端 01 中显示 我的老师将显示的值设置为newValue是什么意思，我尝试了this.value;。然而，它仍然给我错误，另外我尝试更改其中的符号，但老师说这是不正确的，我应该检查该值是否正确，然后将其设置为 newValue。我该如何解决这个问题？我很感激你的帮助。

    private int minLimit;
    private int maxLimit;
    private int value;
    private boolean wrapped;

    public NumberDisplay(int minLimit, int maxLimit) throws IllegalValueException {

        if (maxLimit > minLimit) {
            this.minLimit = minLimit;
            this.maxLimit = maxLimit - 1;
            this.value = minLimit;
            this.wrapped = true;
            // creates new number display with the value minimum limit
            // and the limits between maximum limit. if maximum limit is not greater than
            // minimum limit
            // it should throw exception

        } else {
            throw new IllegalValueException("felaktig");

        }

    }

    public int getValue() {
        return this.value;

        // return the current value on display with integer number
    }

    public void setValue(int newValue) throws IllegalValueException {
        if (newValue < minLimit || newValue > maxLimit) {


            throw new IllegalValueException("Felaktig prova igen set time är felaktig");
            // set the value on display to newValue. if newValue is less greater than minimum
            // limit
            // or greater than value from display then throw exception
        } else {

            if (newValue == minLimit) {
                newValue = minLimit;
            }

        }

    }

    public String getDisplayValue() {

        if (this.value < 11) {
            return "0" + value;
        } else {
            return "" + value;
        }
        // return the current value with 0 infront of the value

    }

    public void increment() {

        if (this.value == maxLimit) {

            this.value = this.minLimit;
            this.wrapped = true;
        } else {

            this.value = +1;
        }

        // increases the display with one value and checks if maximum limit is reached
        // then
        // it should be converted to minimum limit

        // Consider to do the string delightful so all of values sets with as many as
        // numbers
        // the display should have. Values with low numbers should be zeros in front,
        // e.g. clock 9 09:00

    }

    public boolean diWrapAround() {
        if (this.value < maxLimit) {

            return this.wrapped = true;
        } else

            return false;

    }
    // it should return true if the display reached over maximum limit and started
    // from
    // minimum limit , otherwise it should return false,
    // use attribute wrapped to check boolean false or true.

}

Answer 1

enter code here public void setValue(int newValue) throws IllegalValueException {
    if (newValue < minLimit || newValue > maxLimit) {

        throw new IllegalValueException("Felaktig prova igen set time är felaktig");
        // set the current display value to newValue. if newValue is less greater than
        // minimum limit
        // or greater than value from display then throw exception
    } else {

        if (newValue == minLimit ) {

            this.value = newValue;
        }

    }

}

对于想知道答案的人，我更改了 this.value = newValue;检查该值是否正确