- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我正在开发一个项目,并且有两个一起运行的线程。该项目是一个模拟银行,本质上,我们有一个存款线程和一个取款线程。我遇到存款线程频繁运行的问题,导致银行账户余额增加。 (我希望我在现实生活中遇到这个问题。)如何减少线程运行的时间?
这是我的主要类(class):
package bankexample;
import bankexample.depositThread;
public class BankExample {
public static int balance =0 ;
public static void main(String[] args) {
System.out.println("Deposit Thread Withdrawl Thread Balance \n");
System.out.println("-------------- ----------------- --------");
while (true){
Thread d1 = new Thread(new depositThread(1));
Thread d2 = new Thread(new depositThread(2));
Thread d3 = new Thread(new depositThread(3));
Thread w1 = new Thread(new WithdrawThread(1));
Thread w2 = new Thread(new WithdrawThread(2));
Thread w3 = new Thread(new WithdrawThread(3));
Thread w4 = new Thread(new WithdrawThread(4));
d1.start();
d2.start();
d3.start();
w1.start();
w2.start();
w3.start();
w4.start();
}
}
}
以下是取款和存款线程类:
package bankexample;
/**
*
* @author KJ4CC
*/
public class WithdrawThread implements Runnable {
transaction withdraw = new transaction();
int threadNum;
public WithdrawThread(int num){
threadNum = num;
}
public void run(){
withdraw.withdraw(threadNum);
}
}
---------------------------
package bankexample;
import bankexample.transaction;
/**
*
* @author KJ4CC
*/
public class depositThread implements Runnable {
transaction startThread = new transaction();
public static int balance;
int threadNum;
public depositThread(int num){
threadNum = num;
}
@Override
public void run(){
try {
Thread.sleep(100);
startThread.deposit(threadNum);
} catch (Exception e) {
}
}
}
最后她是交易类:
package bankexample;
import java.util.Random;
import java.util.concurrent.locks.ReentrantLock;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.Condition;
import java.util.logging.Level;
import java.util.logging.Logger;
/**
*
* @author KJ4CC
*/
public class transaction extends BankExample {
private Lock accessLock = new ReentrantLock();
private Condition cond = accessLock.newCondition();
private boolean occupied = false;
Random rand = new Random();
public void deposit(int threadNum) throws InterruptedException{
//random amount for amount to deposit into bank mod 200
int amount = rand.nextInt(200);
//locks the thread
//System.out.println("Balance before Deposit " + balance);
accessLock.lock();
try {
//System.out.println(getBalance.getbalance());
//adds the amount to the balance.
if (occupied == false){
occupied = true;
balance = (balance + amount);
//outputs to terminal
System.out.println("Thread " + threadNum + " Deposits " + amount + "\t\t\t\t Balance is " + balance);
occupied = false;
Thread.sleep(10000);
//signals any awiting widthdraw threads
cond.signal();
}
} finally {
//unlocks thread
accessLock.unlock();
}
}
public void withdraw(int threadNum){
//getting a random amount mod50
int amount = rand.nextInt(50);
//locking the thread
accessLock.lock();
try {
//test print out
//checks to see if the amount is less than the balance
if (amount < balance && occupied == false) {
occupied = true;
// System.out.println("Balance before withdraw " + balance);
balance = (balance - amount );
System.out.println("\t\t\tThread " + threadNum + " withdrawls " + amount + "\t Balance is " + balance);
cond.signalAll();
occupied = false;
//if it isnt we can not make a withdraw so we have to wait for a deposit
} else {
System.out.println("\t\t\tThread " + threadNum + " Failed to withdrawl " + amount + "\t Balance is " + balance);
cond.await();
}
//unlock the thread
} catch (InterruptedException ex) {
Logger.getLogger(transaction.class.getName()).log(Level.SEVERE, null, ex);
} finally {
accessLock.unlock();
}
}
}
我尝试让线程在达到锁定条件之前 hibernate ,但不幸的是,它不起作用。
Here is a sample from the output:
Deposit Thread Withdrawl Thread Balance
-------------- ----------------- --------
Thread 1 Failed to withdrawl 4 Balance is 0
Thread 2 Failed to withdrawl 49 Balance is 0
Thread 3 Failed to withdrawl 21 Balance is 0
Thread 4 Failed to withdrawl 13 Balance is 0
Thread 1 Failed to withdrawl 30 Balance is 0
Thread 2 Failed to withdrawl 15 Balance is 0
Thread 3 Failed to withdrawl 18 Balance is 0
Thread 4 Failed to withdrawl 25 Balance is 0
Thread 2 Failed to withdrawl 27 Balance is 0
Thread 1 Failed to withdrawl 9 Balance is 0
Thread 3 Failed to withdrawl 0 Balance is 0
Thread 4 Failed to withdrawl 21 Balance is 0
Thread 1 Failed to withdrawl 31 Balance is 0
Thread 2 Failed to withdrawl 32 Balance is 0
Thread 3 Failed to withdrawl 47 Balance is 0
Thread 4 Failed to withdrawl 8 Balance is 0
Thread 1 Failed to withdrawl 22 Balance is 0
Thread 2 Failed to withdrawl 38 Balance is 0
Thread 3 Failed to withdrawl 43 Balance is 0
Thread 4 Failed to withdrawl 2 Balance is 0
Thread 1 Failed to withdrawl 19 Balance is 0
Thread 2 Failed to withdrawl 39 Balance is 0
Thread 3 Failed to withdrawl 43 Balance is 0
Thread 4 Failed to withdrawl 48 Balance is 0
Thread 1 Failed to withdrawl 45 Balance is 0
Thread 3 Failed to withdrawl 45 Balance is 0
Thread 2 Failed to withdrawl 25 Balance is 0
Thread 4 Failed to withdrawl 21 Balance is 0
Thread 2 Deposits 188 Balance is 188
Thread 3 Deposits 128 Balance is 316
Thread 2 Deposits 54 Balance is 370
Thread 1 Deposits 123 Balance is 493
Thread 3 Deposits 59 Balance is 552
Thread 1 withdrawls 38 Balance is 514
Thread 2 withdrawls 35 Balance is 479
Thread 3 withdrawls 40 Balance is 439
Thread 4 withdrawls 5 Balance is 434
Thread 1 Deposits 179 Balance is 613
Thread 1 Deposits 108 Balance is 1027
Thread 2 Deposits 56 Balance is 919
Thread 1 Deposits 96 Balance is 863
Thread 2 Deposits 101 Balance is 767
Thread 3 Deposits 149 Balance is 1176
Thread 3 Deposits 53 Balance is 666
Thread 2 Deposits 67 Balance is 1277
Thread 1 Deposits 108 Balance is 1385
Thread 3 Deposits 34 Balance is 1277
Thread 2 Deposits 69 Balance is 1466
Thread 3 Deposits 49 Balance is 1561
Thread 4 withdrawls 32 Balance is 1529
Thread 1 Deposits 12 Balance is 1561
Thread 2 Deposits 46 Balance is 1561
Thread 1 Deposits 99 Balance is 15
最佳答案
更大的问题是,在 while(true)
的每次迭代中,您将创建 7 个单独的线程。您基本上在这里生成了无限数量的线程和银行帐户。
每次实例化一个新的 DepositThread
或 WithdrawThread
时,您都会创建一个新的 transaction
对象,每个对象都有自己的私有(private) 锁
有效地不同步任何内容。
public class WithdrawThread implements Runnable {
//creates a new Lock per *Thread*
transaction withdraw = new transaction();
...
}
您的任何线程之间都没有受到适当保护的共享状态。每个 WithdrawThread
/DepositThread
仅尝试通过 transaction
对象获取自己的私有(private)锁。仅当所有线程都可以访问资源时,Lock
才能对资源强制执行互斥。
更好的解决方案是拥有一个 Transaction
对象,该对象的引用作为参数传递给每个线程。
关于java - 如何减少线程运行的时间?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39691066/
好的,所以我想从批处理文件运行我的整个工作环境... 我想要实现什么...... 打开新的 powershell,打开我的 API 文件夹并从该文件夹运行 VS Code 编辑器(cd c:\xy;
我正在查看 Cocoa Controls 上的示例并下载了一些演示。我遇到的问题是一些例子,比如 BCTabBarController ,不会在我的设备上构建或启动。当我打开项目时,它看起来很正常,没
我刚刚开始学习 C 语言(擅长 Java 和 Python)。 当编写 C 程序(例如 hello world)时,我在 ubuntu cmd 行上使用 gcc hello.c -o hello 编译
我在 php 脚本从 cron 开始运行到超时后注意到了这个问题,但是当它从命令行手动运行时这不是问题。 (对于 CLI,PHP 默认的 max_execution_time 是 0) 所以我尝试运行
我可以使用命令行运行测试 > ./node_modules/.bin/wdio wdio.conf.js 但是如果我尝试从 IntelliJ 的运行/调试配置运行它,我会遇到各种不同的错误。 Fea
Error occurred during initialization of VM. Could not reserve enough space for object heap. Error: C
将 Anaconda 安装到 C:\ 后,我无法打开 jupyter 笔记本。无论是在带有 jupyter notebook 的 Anaconda Prompt 中还是在导航器中。我就是无法让它工作。
我遇到一个问题,如果我双击我的脚本 (.py),或者使用 IDLE 打开它,它将正确编译并运行。但是,如果我尝试在 Windows 命令行中运行脚本,请使用 C:\> "C:\Software_Dev
情况 我正在使用 mysql 数据库。查询从 phpmyadmin 和 postman 运行 但是当我从 android 发送请求时(它返回零行) 我已经记录了从 android 发送的电子邮件是正确
所以这个有点奇怪 - 为什么从 Java 运行 .exe 文件会给出不同的输出而不是直接运行 .exe。 当 java 在下面的行执行时,它会调用我构建的可与 3CX 电话系统配合使用的 .exe 文
这行代码 Environment.Is64BitProcess 当我的应用单独运行时评估为真。 但是当它在我的 Visual Studio 单元测试中运行时,相同的表达式的计算结果为 false。 我
关闭。这个问题是opinion-based .它目前不接受答案。 想要改进这个问题? 更新问题,以便 editing this post 可以用事实和引用来回答它. 关闭 8 年前。 Improve
我写了一个使用 libpq 连接到 PostgreSQL 数据库的演示。 我尝试通过包含将 C 文件连接到 PostgreSQL #include 在我将路径添加到系统变量 I:\Program F
如何从 Jenkins 运行 Android 模拟器来运行我的测试?当我在 Execiute Windows bath 命令中写入时,运行模拟器的命令: emulator -avd Tester 然后
我已经配置好东西,这样我就可以使用 ssl 登录和访问在 nginx 上运行的 errbit 我的问题是我不知道如何设置我的 Rails 应用程序的 errbit.rb 以便我可以运行测试 nginx
我编写了 flutter 应用程序,我通过 xcode 打开了 ios 部分并且应用程序正在运行,但是当我通过 flutter build ios 通过 vscode 运行应用程序时,我得到了这个错误
我有一个简短的 python 脚本,它使用日志记录模块和 configparser 模块。我在Win7下使用PyCharm 2.7.1和Python 3.3。 当我使用 PyCharm 运行我的脚本时
我在这里遇到了一些难题。 我的开发箱是 64 位的,windows 7。我所有的项目都编译为“任何 CPU”。该项目引用了 64 位版本的第 3 方软件 当我运行不使用任何 Web 引用的单元测试时,
当我注意到以下问题时,我正在做一些 C++ 练习。给定的代码将不会在 Visual Studio 2013 或 Qt Creator 5.4.1 中运行/编译 报错: invalid types 'd
假设我有一个 easteregg.py 文件: from airflow import DAG from dateutil import parser from datetime import tim
我是一名优秀的程序员,十分优秀!