java - java中如何检查给定的句子是否避免了某个字母？

Question

我一直在试图弄清楚如何查看给定的句子是否是一个避免字母 E 的 lipogram。我已经达到了输入真/假陈述的地步，但它只输出“这句话是不是每次都避免字母 e 的 Lipogram，无论输入是否包含 e。我做错了什么？

boolean avoidsE = false, hasE = true, avoidsS = false, containsS = true;

for(int i = 0; i < sentence.length(); i++)
{
  if (sentence.charAt(i) == 'e')
  hasE = true;
  else
  avoidsE = false;
}

if (hasE = true)
System.out.println("This sentence is not a Lipogram avoiding the letter e. ");
else if (avoidsE = false)
System.out.println("This sentence is a Lipogram avoiding the letter e! ");

Answer 1

if (hasE == true) // "=" is to assign, you want to use "==" here to check  
    System.out.println("This sentence is not a Lipogram avoiding the letter e. "); 
else if (avoidsE == false) //same here   
    System.out.println("This sentence is a Lipogram avoiding the letter e! ");