Java 将 switch 语句转换为另一种类型

Question

我对 Java 很陌生。我现在正在上我的第一堂 Java 课。

我正在尝试找到一种使用 switch 指令以外的东西重写以下代码的方法。此代码与数独游戏相关。我需要问这个问题几次，然后我需要根据答案计算统计数据。

请注意，我在初级类，无法使用高级 Java 代码。

String response = "Y";

while (response.toLowerCase().equals("y"))
{

    System.out.println("Please choose the game level");
    System.out.println(" -----------------------------------");
    System.out.println(" Enter 1 for Sudoku level Beginner");
    System.out.println(" Enter 2 for Sudoku level Advanced");
    System.out.println(" Enter 3 for Sudoku level Expert");
    System.out.println(" -----------------------------------");

    Sudoku = sudoku.nextInt();

    if (Sudoku == 1) {

        int choice1 = 0;

        nbGames_Easy++;

        System.out.println("Have you won the game ?");

        System.out.print(" Enter 4 for yes ");

        System.out.print(" Enter 5 for no ");

        choice1 = sudoku.nextInt();

        sudoku.nextLine();

        switch (choice1)

        {

            case 4:

                nbGamesEasy_Finished++;

                successRate_Easy = nbGamesEasy_Finished / nbGames_Easy * 100;

                System.out.println("How many time did you take to fill the grid ?");

                System.out.println("The time must be in minutes");

                String display5 = sudoku.nextLine();

                resolutionTime_easy = (nbGamesEasy_Finished * resolutionTime_easy) + Integer.parseInt(display5) / (nbGamesEasy_Finished);

                break;

            case 5:

                successRate_Easy = nbGamesEasy_Finished - 1 / nbGames_Easy * 100;

            default:

                break;
        }

    }
}

Answer 1

对于初学者来说，您可以将 switch 语句替换为 if-else if 语句，就像您之前在代码中所做的那样。您可以尝试如下所示:

if (choice1 == 4){

       nbGamesEasy_Finished++;

       successRate_Easy = nbGamesEasy_Finished / nbGames_Easy * 100;

       System.out.println("How many time did you take to fill the grid ?");

       System.out.println("The time must be in minutes");

       String display5 = sudoku.nextLine();

       resolutionTime_easy = (nbGamesEasy_Finished * resolutionTime_easy) + Integer.parseInt(display5) / (nbGamesEasy_Finished);

}
else if (choice1 == 5){

       successRate_Easy = nbGamesEasy_Finished - 1 / nbGames_Easy * 100;

}
else {

       //default

}