amazon-web-services - 做 dynamoattribute.UnmarshalMap 时关系总是为零

Question

我有两个结构。 sample 和测试。 “样本”具有“测试”类型的关系。当我尝试做'dynamoattribute.UnmarshalMap'时，关系总是为零。您能否建议如何填充关系(在这种情况下为“测试”)？

package main

import (
    "fmt"

    "github.com/aws/aws-sdk-go/aws"
    "github.com/aws/aws-sdk-go/service/dynamodb"
    "github.com/aws/aws-sdk-go/service/dynamodb/dynamodbattribute"
)

type Sample struct {
    SampleId string `jsonapi:"attr,sampleId,omitempty" dynamodbav:"sample_id"`
    Test     *Test  `jsonapi:"relation,test"`
}

type Test struct {
    TestId string `jsonapi:"attr,testId,omitempty" dynamodbav:"test_id"`
}

func main() {
    var m map[string]*dynamodb.AttributeValue
    m = make(map[string]*dynamodb.AttributeValue)

    m["sample_id"] = &dynamodb.AttributeValue{
        S: aws.String("sample1"),
    }

    m["test_id"] = &dynamodb.AttributeValue{
        S: aws.String("test"),
    }

    sam := Sample{}

    err := dynamodbattribute.UnmarshalMap(m, &sam)
    if err != nil {
        fmt.Println(err)
    }

    fmt.Println(sam)
}

Answer 1

package main

import (
    "fmt"

    "github.com/aws/aws-sdk-go/aws"
    "github.com/aws/aws-sdk-go/service/dynamodb"
    "github.com/aws/aws-sdk-go/service/dynamodb/dynamodbattribute"
)

type Sample struct {
    SampleId string `jsonapi:"attr,sampleId,omitempty" dynamodbav:"sample_id"`
    Test     *Test  `jsonapi:"relation,test"`
}

type Test struct {
    TestId string `jsonapi:"primary,testId" dynamodbav:"test_id"`
}


func main() {
    var m map[string]*dynamodb.AttributeValue
    m = make(map[string]*dynamodb.AttributeValue)   

    m["sample_id"] = &dynamodb.AttributeValue{
        S: aws.String("sample1"),
    }

    var mTest map[string]*dynamodb.AttributeValue
    mTest = make(map[string]*dynamodb.AttributeValue)

    mTest["test_id"] = &dynamodb.AttributeValue{
        S: aws.String("test1"),
    }

    m["test"] = &dynamodb.AttributeValue{
        M: mTest,
    }

    sam := Sample{}

    err := dynamodbattribute.UnmarshalMap(m, &sam)
    if err != nil {
        fmt.Println(err)
    }

    fmt.Println(sam)
}