Java : Error in Cursor automatically move from one TextField to other

Question

当我输入 TextField 7 字符时，光标自动移动到下一个 TextField。但在我的代码中，我的光标没有转到 nextField。(我知道我不能使用 addKeyListener，所以尝试使用 DocumentListener 来执行此代码)

lbltext1  = new JLabel("Text1");
panel.add(lbltext1, "cell 0 1,alignx trailing");
final int maxSize =7 ;
for (int i = 0; i < 1; i++) {
    final JTextField txtText1 = new JTextField();
    NavigationFilter filter = new NavigationFilter() {
        @Override
        public void setDot(FilterBypass fb, int dot, Bias bias) {
            if (dot >= maxSize) {
                fb.setDot(0, bias);
                txtText1.transferFocus();
                return;
            }
            fb.setDot(dot, bias);
        }

        @Override
        public void moveDot(FilterBypass fb, int dot, Bias bias) {
            if (dot >= maxSize) { 
                fb.setDot(0, bias);
                txtText1.transferFocus();
                return;
            }
            fb.moveDot(dot, bias);
        }
    };      
    txtText1.addFocusListener(new FocusAdapter() {
            @Override
            public void focusLost(FocusEvent arg0) {

                if (txtText1.getText().equals("")) {
                    txtDate.setText("");
                } else {
                    SwingWorker<?, ?> job = new UIQuery();
                job.execute();
                }
         }
    });         
    txtText1.setNavigationFilter(filter);
    ((AbstractDocument) txtText1.getDocument()).setDocumentFilter(new DocumentSizeFilter(maxSize));   
    panel.add(txtText1, "cell 1 1,growx");
    txtText1.setColumns(10);
}   
JLabel lblText2 = new JLabel("Production Date");
panel.add(lblText2, "cell 0 2,alignx trailing");
txtText2 = new JTextField();
panel.add(txtText2, "flowx,cell 1 2,growx");
txtText2.setColumns(10);
txtText2.addFocusListener(new TextBoxGainedFocusEventSinglePreview());
txtText2.getDocument().addDocumentListener(new TextBoxDataChangedEventSinglePreview());

请指教我该如何修改。谢谢

Answer 1

因此，这是一个简单的概念证明，当字段的 Document 长度 > 6 时，它将焦点从当前组件移动到下一个组件

import java.awt.KeyboardFocusManager;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JTextField;
import javax.swing.SwingUtilities;
import javax.swing.event.DocumentEvent;
import javax.swing.event.DocumentListener;

public class Test {

    public static void main(String[] args) {
        new Test();
    }

    public Test() {
        SwingUtilities.invokeLater(new Runnable() {
            @Override
            public void run() {
                JFrame frame = new JFrame("Test");
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.add(new TestPane());
                frame.pack();
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);
            }
        });
    }

    public class TestPane extends JPanel {

        public TestPane() {
            JTextField field1 = new JTextField(7);
            JTextField field2 = new JTextField(7);

            add(field1);
            add(field2);

            field1.getDocument().addDocumentListener(new DocumentListener() {
                @Override
                public void insertUpdate(DocumentEvent e) {
                    if (e.getDocument().getLength() > 6) {
                        //field1.transferFocus();
                        KeyboardFocusManager.getCurrentKeyboardFocusManager().focusNextComponent();
                    }
                }

                @Override
                public void removeUpdate(DocumentEvent e) {
                }

                @Override
                public void changedUpdate(DocumentEvent e) {
                    if (e.getDocument().getLength() > 6) {
                        //field1.transferFocus();
                        KeyboardFocusManager.getCurrentKeyboardFocusManager().focusNextComponent();
                    }
                }
            });
        }

    }
}

当某些东西不起作用时，首先删除测试它不需要的所有内容(即DocumentFilter和NavigationFilter)，让它以隔离状态工作一旦您知道它正在工作，就可以一次重新引入其他元素并确保不会出现任何问题。

DocumentSizeFilter 可能会干扰它，但我没有足够的上下文来 100% 确定