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java - Android Studio : Try-catch exception crashes application

转载 作者:行者123 更新时间:2023-12-01 20:27:09 29 4
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我正在测试代码内部的一些漏洞,并尝试通过在用户输入无效时抛出异常来修复它们。现在,当我实现 try-catch 并在手机上运行该应用程序时,当我输入无效输入时,它会崩溃。

我假设我的代码没有捕获 addData 方法的异常。是否有其他方法来实现异常,或者如何才能从 addData 方法捕获异常?

package com.odisee.photoboothapp;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.RadioButton;
import android.widget.RadioGroup;
import android.widget.EditText;
import android.widget.Toast;

import com.odisee.photoboothapp.fontchanger.FontChangeTextView;

public class Form_Database extends AppCompatActivity {
DatabaseHelper myDb;

int selectedId;
RadioGroup test;
RadioButton editEducation;
EditText editName, editSurname, editEmail;
Button btnAddData;

@Override
protected void onCreate(Bundle savedInstanceState) throws IllegalArgumentException {
super.onCreate(savedInstanceState);
getSupportActionBar().hide();
setContentView(R.layout.activity_form__database);

myDb = new DatabaseHelper(this);

test = (RadioGroup)findViewById(R.id.radioButtonChoice);

editName = (EditText)findViewById(R.id.edit_Name);
editSurname = (EditText)findViewById(R.id.edit_Surname);
editEmail = (EditText)findViewById(R.id.edit_Email);


btnAddData = (Button)findViewById(R.id.btnSend);
try {
addData();
}
catch(IllegalArgumentException e) {
Toast.makeText(Form_Database.this,"Data not inserted" + e.getMessage(),Toast.LENGTH_LONG).show();
}
}

public void addData() {
btnAddData.setOnClickListener(
new View.OnClickListener() {
@Override
public void onClick(View v) {
if(editName.getText().toString().contains("DROP")) {
throw new IllegalArgumentException("SQL Exceptie!");
}
else {

selectedId = test.getCheckedRadioButtonId();
editEducation = (RadioButton)findViewById(selectedId);
boolean isInserted = myDb.insertData(editName.getText().toString(), editSurname.getText().toString(), editEmail.getText().toString(), editEducation.getText().toString());

sendEmail();

if(isInserted == true) {
Toast.makeText(Form_Database.this,"Data inserted",Toast.LENGTH_LONG).show();
}
else {
Toast.makeText(Form_Database.this,"Data not inserted",Toast.LENGTH_LONG).show();
}
}
}
}
);
}

public void sendEmail() {
//Getting content for email
String email = editEmail.getText().toString();
String subject = "testberichtje voor lorenzo";
String message = "testberichtje voor lorenzo";

//Creating SendMail object
SendMail sm = new SendMail(this, email, subject, message);

//Executing sendmail to send email
sm.execute();
}

}

05-01 17:58:17.021 30232-30232/com.odisee.photoboothapp E/AndroidRuntime: FATAL EXCEPTION: main Process: com.odisee.photoboothapp, PID: 30232 java.lang.IllegalArgumentException: SQL Exceptie! at com.odisee.photoboothapp.Form_Database$1.onClick(Form_Database.java:55) at android.view.View.performClick(View.java:5697) at android.widget.TextView.performClick(TextView.java:10826) at android.view.View$PerformClick.run(View.java:22526) at android.os.Handler.handleCallback(Handler.java:739) at android.os.Handler.dispatchMessage(Handler.java:95) at android.os.Looper.loop(Looper.java:158) at android.app.ActivityThread.main(ActivityThread.java:7224) at java.lang.reflect.Method.invoke(Native Method) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1230) at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1120)

最佳答案

尝试使 catch 更通用,以便您可以实际捕获错误,然后打印堆栈跟踪以便您可以看到问题:

try{
//Try to do something on here
}catch(Exception error1) {
Log.e(TAG, "The exception caught while executing the process. (error1)")
error1.printStackTrace();
}

关于java - Android Studio : Try-catch exception crashes application,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43721683/

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