java - 在一维游戏中实现第二艘战舰 "River Battleship"

Question

是否有人能够为我提供一种简单的方法，在我设计的只有一个敌人的游戏中实现第二艘敌方战舰，这是我目前的代码:

import java.util.*; //Scanner that reads user input

public static void main(String[] arg) 
    {
        int riverLength = promptForInt("Select Length for River ") ; //Variable that stores the user input when prompted
        int [] shipArray = new int[riverLength] ; //User input is used to create an Array, i.e. River Size
        int battleshipCoordinates = new Random().nextInt(riverLength) ; //Random number is found within the Array (Where the enemy ship will hide) 

        shipArray[battleshipCoordinates] = 1 ; 
        boolean hit = false ; //Statement created for ship hit and default to false
        int playerSelection; //int Variable declared

        do
       {
           displayRiver (shipArray, false);
           playerSelection = promptForInt(String.format("Select location to launch torpedo (1 - %d) ", riverLength));
           playerSelection = playerSelection -1 ; 

           if(shipArray[playerSelection] == 1 ) //if a user strikes the Enemy (Case 1) correctly they system informs them of a strike
           {
            System.out.println("Battleship Sunk!");
            hit = true; 
            displayRiver(shipArray, true);
           }
           else if(shipArray[playerSelection] == -1)
           {
            System.out.println("Location already Hit! Try again.");
           }
           else if(shipArray[playerSelection] == 0)
           {
            System.out.println("Miss!");
            shipArray[playerSelection] = -1 ; 
           }

       } while(!hit); 




    }
}

Answer 1

第 0 步 - 创建一艘新战舰并将它们像第一艘战舰一样放置在阵列上。

第 1 步 - 将 boolean 命中更改为等于 2 的 int。

第 2 步 - 不要切换命中，而是在击中船只时将其减少 1，然后设置数组上的该位置为 0。

第 3 步 - 调整你的逻辑，这样除非击中 <1，否则你不会获胜