xml - GoLang XML编码(marshal)处理自定义(无根元素的编码(marshal))

Question

如何在没有根元素的情况下进行编码(marshal)？

type Ids struct {
  Id []string `xml:"id"`
}

IdsStr, _ := xml.Marshal(&Ids{[]string{"test1", "test2"}})

输出IdsStr为:

<Ids><id>test1</id><id>test2</id></Ids>

应该没有Ids元素:

<id>test1</id><id>test2</id>

Playground

Answer 1

...But how can I set voluntary xml names for elements? Vals []id xml:"idSomeOther" returns id after xml marshaled because it's name of type... I need to customize type id to type IdXml but xml marshaled should return id. How can I get it?

您可以使用 XMLName xml.Name，标签 xml:",chardata"(等)来自定义 struct

type Customs struct {
    Vals []CustomXml
}

type CustomXml struct {
    XMLName xml.Name
    Chardata string `xml:",chardata"`
}

func main() {
    customs := Customs{
        []CustomXml{
            {XMLName: xml.Name{Local: "1"}, Chardata: "XXX"},
            {XMLName: xml.Name{Local: "2"}, Chardata: "YYY"}},
    }
    res, _ := xml.Marshal(customs.Vals)
    fmt.Println(string(res))
}

0输出

<1>XXX</1><2>YYY</2>

Playground
👉🏻另外，在 src/encoding/xml/上查找示例。