java - 尽管条件失败，While 循环仍继续运行

Question

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    String sent = "y";
    int a = 0;
    int b = 0;
    System.out.println("Welcome!\nThis program compares two letters in a sentence.");
    while(!sent.equalsIgnoreCase("X")) {
        System.out.print("Enter a sentence or X to exit: ");
        sent = input.next();

        System.out.print("Enter the numeric location of the first letter: ");
        while(!input.hasNextInt()) { 
            System.out.println("Error! Please enter a number not text!");
            input.nextLine(); 

            System.out.print("Enter the numeric location of the first letter: "); 
        }
        a = input.nextInt(); 


        System.out.print("Enter the numeric location of the second letter: ");
        while(!input.hasNextInt()) { 
            System.out.println("Error! Please enter a number not text!");
            input.nextLine(); 

            System.out.print("Enter the numeric location of the second letter: "); 
        }
        b = input.nextInt(); 

       System.out.println();

       char c = sent.charAt(a);
       char d = sent.charAt(b);

       if(c==d) {
           System.out.println(c+" and "+d+" are identical.\n");
       }
       else {
           System.out.println(c+ " and "+ d + " are unique characters. \n");
       }    

    }
    System.out.print("GoodBye!");


}

即使你输入 X，这个循环也会继续运行，我不知道为什么。此外，当您输入文本而不是数字时，错误消息将如下所示:错误!请输入数字而不是文字!输入第一个字母的数字位置:错误!请输入数字而不是文字!输入第一个字母的数字位置:

只有第三句话会接受用户输入。

Answer 1

这段代码sent = input.next()没有阅读整个句子。它只读一个字。尝试使用 nextLine() 代替。

此外，您应该在设置 sent 后立即测试退出条件。