json - Go Gin将json响应转换为base64

Question

我试图发送数据库查询数据作为json响应。这是我的 Controller :

import (
    "fmt"
    "github.com/json-iterator/go"
    "log"
)

func GetNewsPapers()  []byte{
    db := GetDB()

    var json = jsoniter.ConfigCompatibleWithStandardLibrary

    rows, err := db.Queryx(`SELECT title, language, ranking, slug, search_term, logo_url FROM public.news_newspaper`)
    if err != nil {
        log.Println(err)
    }

    defer rows.Close()
    tableData := make([]map[string]interface{}, 0)

    for rows.Next() {
        entry := make(map[string]interface{})
        err := rows.MapScan(entry)
        if err != nil {
            log.Println(err)
        }
        tableData = append(tableData, entry)
    }

    jsonData, _ := json.Marshal(tableData)

    fmt.Println(string(jsonData))  // printing expected json
    err = rows.Err()
    if err != nil {
        panic(err)
    }
    return jsonData
}

和

func (n *NewsPaperController) GetList(c *gin.Context) {
    value := database.GetNewsPapers()
    c.JSON(http.StatusOK, value)
}

问题是我正在获取base64字符串作为响应，而不是我期望的json对象。如果将 value转换为如下所示的字符串，则会得到人类可读的值。

c.JSON(http.StatusOK, string(value))

但是整个响应都以这样的字符串编码:

"[{\"language\":\"en\",\"logo_url\":\"..\",\"ranking\":2,\"search_term\":\"..\",\"slug\":\"..\",\"title\":\"....\"}]

我如何获得json响应，如下所示:

 [{"language":"en","logo_url":"..","ranking":2,"search_term":"..","slug":"..","title":".."} ] 

Answer 1

func (c *Context) JSON(code int, obj interface{})

JSON serializes thegiven struct as JSON into the response body. It also sets theContent-Type as "application/json".

c.JSON()序列化为JSON，使用前无需解码。在 tableData中使用 c.JSON()

func GetNewsPapers()  []map[string]interface{}{
    // your existing code
    return tableData
}

func (n *NewsPaperController) GetList(c *gin.Context) {
    value := database.GetNewsPapers()
    c.JSON(http.StatusOK, value)
}

并使用 %#v，您可以看到该值的Go语法表示形式，您还将在其中找到转义字符

fmt.Printf("%#v", string(jsonData))