ios - 将图像从JSON Url显示到TableView

Question

为此收到3个错误

1) " [__NSCFString size]: unrecognized selector sent to instance "

2) " [NSNull length]: unrecognized selector sent to instance "

3) " [__NSCFString size]: unrecognized selector sent to instance "

下面是我的代码。你能帮我爱上这个问题吗？

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView {
    return 1;
}
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:  (NSInteger)section {
    return matchesProfileArr.count;;
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
    static NSString *CellIdentifier = @"Cell";
    displayCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier
    forIndexPath:indexPath];

    if(!cell) {
        cell = [[displayCell alloc] initWithStyle:UITableViewCellStyleDefault
        reuseIdentifier:CellIdentifier];
    }

    NSMutableDictionary *dict= [matchesProfileArr objectAtIndex:indexPath.row];            
    NSMutableDictionary *dictdetails=[dict objectForKey:@"ABSAdvancedSearch"];

    cell.lblAge.text = [dictdetails objectForKey:@"age"];
    cell.lblLocation.text = [dictdetails objectForKey:@"CustomerCity"];
    cell.lblProfession.text = [dictdetails objectForKey:@"rb_profession_title"];
    cell.lblEducation.text = [dictdetails objectForKey:@"rb_education_title"];
    cell.lblFullName.text = [dictdetails objectForKey:@"Username"];
    cell.profileImage.image = [dictdetails objectForKey:@"profile_pic"];

    return cell;
}

Answer 1

dispatch_async(dispatch_get_global_queue(0,0), ^{
    NSData * data = [[NSData alloc] initWithContentsOfURL: [NSURL URLWithString:[dictdetails objectForKey:@"profile_pic"]]];
    if ( data == nil )
        return;
    dispatch_async(dispatch_get_main_queue(), ^{

        cell.image = [UIImage imageWithData: data];
    });

});

请使用此代码，如果您使用dispatch_async，您的用户界面将不会卡住